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enyata [817]
3 years ago
14

Multiplying Polynomials by Monomials: 2x (5x-2) = 10x-4x

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
8 0

Answer:

yvsgctdyghvrtj teefseqtf

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I need help on this question ​
nadezda [96]

Answer:

(12.2,-6.4)

Step-by-step explanation:

The results from Desmos are as shown.

The displayed values are (12.294, -6.353)

4 0
3 years ago
Ve the equation. 3c + 1 = c +1​
yKpoI14uk [10]
Subtract C in both sides:
2c + 1 = 1

Subtract 1 on both sides
2c = 0

The solution is:
x = 0

Hope this helped
4 0
3 years ago
8..................................
ser-zykov [4K]

Answer:

The answer is 2x^{3}y^{-2}\sqrt{6}

Step-by-step explanation:

∵ √24 = 2√6

∵ \sqrt{x^{6}}=(x^{\frac{1}{2}})^{6}=x^{3}

∵ \sqrt{y^{-4}}=(y^{\frac{1}{2}})^{-4}=y^{-2}

∴ \sqrt{24x^{6}y^{-4}}=2x^{3}y^{-2}\sqrt{6}

5 0
3 years ago
Arrange the circles (represented by their equations in general form) in ascending order of their radius lengths. X2 y2 − 2x 2y −
Colt1911 [192]

Circles (represented by their equations in general form) in ascending order of their radius lengths can be arranged as first-fifth-second-forth-third-seventh-sixth.

<h3>What is the equation of circle?</h3>

The equation of the circle is the equation which is used to represent the circle in the algebraic equation form with the value of center point in the coordinate plane and measure of radius.

The standard form of the equation of the circle can be given as,

(x-h)^2+(y-k)^2=r^2

Here (h,k) is the center of the circle and (r) is the radius of the circle.

Lets arrange the first equation, in standard form of equation of circle as,

x^2 +y^2 - 2x+ 2y -1 = 0 \\(x^2 - 2x) +(y^2+ 2y )= 1\\(x^2 - 2x+1) +(y^2+ 2y +1)= 1+1+1\\(x-1)^2+(y+1)^2=(\sqrt{3})^2

The radius of this circle is √(3).

Lets arrange the second equation, in standard form of equation of circle as,

x^2 +y^2 - 4x+ 4y - 10 = 0  \\(x^2 - 4x) +(y^2+ 4y )= 10\\(x^2 - 4x+4) +(y^2+ 4y +4)= 10+4+4\\(x-2)^2+(y+2)^2=(\sqrt{18})^2

The radius of this circle is √(18).

Lets arrange the third equation, in standard form of equation of circle as,

x^2 +y^2 - 8x - 6y - 20 = 0   \\(x^2 - 8x) +(y^2-6y )= 20\\(x^2 - 8x+16) +(y^2- 6y +9)= 10+16+9\\(x-4)^2+(y-3)^2=(\sqrt{45})^2

The radius of this circle is √(45).

Similarly, radius of the forth, fifth, sixth and seventh circle is √(23), √(5), √(117) and √(46) units.

Hence, the circles (represented by their equations in general form) in ascending order of their radius lengths can be arranged as first-fifth-second-forth-third-seventh-sixth.

Learn more about the equation of circle here;

brainly.com/question/1506955

3 0
2 years ago
Read 2 more answers
Questions on attached photo.<br>​
Vinil7 [7]

Answer:

0

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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