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Naddika [18.5K]

3 years ago

15

Find the parabola of the form y = ax2 + b which best fits the points (1, 0), (3, 2), (4, 4) by minimizing the sum of squares, s,

given by

1 answer:

DiKsa [7]3 years ago

8 0

<span>S= (a+b)^2+(4a+b-2)^2+(9a+b-4)^2 98a+14b-44=0 14a+3b-6=0 a=24/49, b=-2/7 y = (24/49)x^2-(2/7)</span>

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Llana [10]

I think it’s the first one.

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2 years ago

Solve and check.

Thepotemich [5.8K]

C/3 = 6 1/7

Multiply 3 to both sides:

C = 6 1/7 * 3

Convert 6 1/7 into an improper fraction:

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STALIN [3.7K]

Answer: 4cm x 4cm x 4cm = 64cm

Step-by-step explanation:

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2 years ago

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Factor each.<br><br><br> Please help!

Naddika [18.5K]

Answer:

1) The factors of $x^2-3x+2=0$ are $\mathbf{(x-1)(x-2)=0}$

Option C is correct.

3) The factors of $x^2+2x-8=0$ are $\mathbf{(x-2)(x+4)=0}$

Option B is correct.

Step-by-step explanation:

1) Factor : $x^2-3x+2=0$

For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.

The middle term : -3x

We can break them as (-2x)( -x)

Solving:

$x^2-3x+2=0\\x^2-2x-x+2=0\\x(x-2)-1(x-2)=0\\(x-1)(x-2)=0$

So, factors of $x^2-3x+2=0$ are $\mathbf{(x-1)(x-2)=0}$

Option C is correct.

3) Factor: $x^2+2x-8=0$

For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.

The middle term : 2x

We can break them as (4x)( -2x)

Solving

$x^2+2x-8=0\\x^2+4x-2x-8=0\\x(x+4)-2(x+4)=0\\(x-2)(x+4)=0$

So, factors of $x^2+2x-8=0$ are $\mathbf{(x-2)(x+4)=0}$

Option B is correct.

7 0

2 years ago

3. The table gives the coordinates of a

marin [14]

Answer:

B

Step-by-step explanation:

Look at the X and Y coordinates carefully. X and Y coordinates are swapped and Y coordinate got negative sign.

4 0

2 years ago