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3 years ago

HELP ME PLEASE Again lol

Mathematics

1 answer:

KatRina [158]3 years ago

4 0

False
true
false
i could be wrong but i’m 85% certain

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Colin surveyed 12 teachers at school to determine how much each person budgets for lunch. He records his results in the table. W

zmey [24]

Answer:

As mean and median are equal, so the data will be in normal distribution in shape of a symmetrical "bell curve".

Step-by-step explanation:

The given data: 10 5 8 10 12 6 8 10 15 6 12 18

Mean is the simple average of all data. As, there are total 12 data, so the Mean will be: $\frac{10+5+8+10+12+6+8+10+15+6+12+18}{12}= \frac{120}{12}=10$

For finding the Median, first we need to rearrange the data according to the numerical order and then identify the middle value. So........

5 6 6 8 8 10 10 10 12 12 15 18

Here the middle values are 10 and 10. So, the median will be the average of those two middle values.

Thus, Median $=\frac{10+10}{2}=\frac{20}{2}=10$

We can see that, the relationship between the mean and the median is "they are equal". So, the data will be in normal distribution and the shape will be symmetrical "bell curve".

8 0

3 years ago

Read 2 more answers

Will mark Brainliest!

Anettt [7]

Answer:a=2.1 :)

Step-by-step explanation:a+(-1.6)=-3.7

+1.6 +1.6

a=-2.1

5 0

3 years ago

Expand.If necessary combine like terms.(1+6x)(1-6x)

Anastaziya [24]

Answer:

-36x^2+1

Step-by-step explanation:

(1+6x)(1-6x)

= 1^2(6x)^2

= -36x^2+1

6 0

3 years ago

Read 2 more answers

#1). Yasmine plans to attend a four-year public university. She expects she will need to contribute $9,000 annually to her educa

Nina [5.8K]

The answer to #1 is D.

The answers to #2 is B,C,D,F.. I'm not sure what the remainder of G says..

3 0

3 years ago

Read 2 more answers

Suppose that many large samples are taken from a population and that the

rewona [7]

Answer:

$0.22 -1 *0.029 =0.191$

$0.22 +1 *0.029 =0.249$

And the best option would be:

D. (0.191 to 0.249)

Step-by-step explanation:

For this case we know that the mean is:

$\bar X = 0.22$

And the standard error is given by:

$SE = 0.029$

We want to construct a 68% confidence interval so then the significance level would be :

$\alpha=1-0.68 = 0.32$ and $\alpha/2 =0.16$ . The confidence interval is given by:

$\bar X \pm z_{\alpha/2} SE$

Now we can find the critical value using the normal standard distribution and we got looking for a quantile who accumulate 0.16 of the area on each tail and we got:

$z_{\alpha/2}= 1$

And replacing we got:

$0.22 -1 *0.029 =0.191$

$0.22 +1 *0.029 =0.249$

And the best option would be:

D. (0.191 to 0.249)

5 0

3 years ago