B) 7 would make it true, since both 42/54 and 7/9= 0.77 repeating
Answer:
e. reject the null hypothesis the p value is less than 0.05. therefore the difference is significant.
Step-by-step explanation:
given that after comparing response times between the audio and picture portions of the MIT test, the t-test resulted in a t-value of 2.97.
test statistic t = 2.97
Sample size n =250
Critical value of t at 95% is 1.96
We find that test statistic absolute value is greater than 1.96
So p value would be less than 0.05
This implies that null hypothesis stands in the rejected region.
So reject null hypothesis would be correct conclusion. Sample size cannot be said to be small as more than 30 itself is a good sample size.
e. reject the null hypothesis the p value is less than 0.05. therefore the difference is significant.
Answer:
Therefore the probability that a randomly selected student has time for mile run is less than 6 minute is 0.0618
Step-by-step explanation:
Normal with mean 6.88 minutes and
a standard deviation of 0.57 minutes.
Choose a student at random from this group and call his time for the mile Y. Find P(Y<6)
y ≈ normal (μ, σ)
The z score is the value decreased by the mean divided by the standard deviation
Therefore the probability that a randomly selected student has time for mile run is less than 6 minute is 0.0618
Answer:
A.
Step-by-step explanation:
$15 rental fee added to the 12.75 per hour. you have to multiply the 12.75 times the amount of hours rented, which we don't know yet so that's variable x. then he has only $45 to spend so it has to be equal to or less than that.
Answer:
153.86
Step-by-step explanation:
formula - A = π × r2
3.14 x 7^2
= 153.86
