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mestny [16]
3 years ago
12

The length of the hypotenuse of a 30 60 90 triangle is 11. What is the perimeter?

Mathematics
1 answer:
valentina_108 [34]3 years ago
5 0

Answer:

Perimeter of the triangle is 26.015\\ units

Step-by-step explanation:

Given a 30-60-90 degree angled triangle  

Let us calculate the length of side opposite the 30 degree angle

= \frac{1}{2} *hypotenuse

= \frac{1}{2} * 11\\= 5.5 units

length of side opposite the 60 degree angle

= 5.5 * \sqrt{3} \\= 5.5 * 1.73\\= 9.515 units

The perimeter of a triangle is equal to the sum of length of all three sides

Thus, the perimeter of this 30-60-90 degree angled triangle  is

11 + 5.5 + 9.515\\= 26.015\\ units

Thus, the  perimeter of the triangle is 26.015\\ units

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The formula for the area of a triangle is 1/2bh=A. Which of the following is not a possible first step to rearrange this formula
yarga [219]

We want to put b alone on one side of the equation.

If we multiply by 1/2, we get 1/4bh = A/2. Not only did we not remove a variable from the left side, we made it even more complicated.

So the answer is A.

7 0
3 years ago
Find the product. (n 7)2 n² 14n 14 2n² 14n 49 n² 14n 49.
Marianna [84]

The product of \rm (n+7)^2 is \rm n^2+14n+49.

Given

The product of \rm (n+7)^2.

<h3>What is multiplication?</h3>

Multiplication is the process of calculating the product of two or more numbers.

The multiplication of numbers say, ‘a’ and ‘b’, is stated as ‘a’ multiplied by ‘b’.

The product of \rm (n+7)^2 is given by;

\rm =(n+7)^2\\\\=(n+7)\times (n+7)\\\\= n(n+7)+7(n+7)\\\\=n^2+7n+7n+49\\\\=n^2+14n+49

Hence, the product of \rm (n+7)^2 is \rm n^2+14n+49.

To know more about Multiplication click the link given below.

brainly.com/question/19943359

8 0
2 years ago
Transform the literal equation to solve for f.<br><br><br> fg + c = d
wolverine [178]

Answer:

f=(d-c)/g

Step-by-step explanation:

fg+c=d

fg=d-c

f=(d-c)/g

4 0
2 years ago
The Johnson twins were born eleven years after their older sister. This​ year, the product of the three​ siblings' ages is exact
vodka [1.7K]
So there are 3 siblings: the first twin, the second twin, and their older sister.

Since the sister is older by 11 years, you can represent their relationship with the following equation;
age of twin = age of older sister - 11
t = s - 11

Representing this next part may be a little hard to show, but i'll do my best :)

Adding the ages together can be represented like this;
total age = t + t + s
If the product of their ages ( t * t * s ) is 1181 more than the sum, you can show it like this:
t * t * s = (t + t + s) + 1181
Now you substitute in (s - 11) for t because s = t - 11.
t * t * s = (t + t + s) + 1181\\&#10;(s-11) * (s-11) * s = ((s-11) + (s-11) + s) + 1181\\&#10;(s^{2}-22x+121)*s=s+s-11-11+1181\\&#10;s^{3}-22s^{2}+121s-2s=1159\\&#10;s^{3}-22s^{2}+118s-1159=0
Factor:
Since it's a third-degree equation, I just entered it into a polynomial solver in my calculator. There was only one factor listed, x = 19. Using (s - 19) = 0 as a factor, the equation becomes the following:
s^{3}-22s^{2}+118s-1159=0\\&#10;(s-19)(s^{2}-3s+61)=0
Using the quadratic formula, you get:
s= \frac{-b(+-)\sqrt{b^{2}-4ac}}{2a}\\&#10;s= \frac{-(-3)(+-)\sqrt{(-3)^{2}-4(1)(61)}}{2*1}\\&#10;s= \frac{3(+-)\sqrt{(9)-244}}{2}\\&#10;s= \frac{3(+-)\sqrt{-235}}{2}

Since you have a square root of a negative number, the answer will be imaginary. You cannot have an age that is imaginary, so the age of the older sister (s) is 19 years.

Because t = s - 11, that means that t = (19) - 11 = 8.
t is the age of the twins, so the twins are 8 years old.
8 0
3 years ago
Can you help me with this please..
jonny [76]

Answer:

0.5

Step-by-step explanation:

Ok, so it's asking for what (1/(x-1) - 2/(x^2-1)) approaches as x approaches 1. Before we deal with the limit, let's simplify the inside.

We want to combine the two fractions into one fraction. Therefore, we need a common denominator.

1/(x-1) is equal to (x+1)/((x+1)(x-1) is equal to (x+1)/(x^2-1).

the inside expression is therefore (x+1)/(x^2-1) - 2/(x^2-1)

which simplifies to (x-1)/(x^2-1).

and that simplifies further to 1/(x+1).

Now this is a continuous function when x = 1, so to find the limit as x approaches 1 of this function, we can by definition just plug 1 in.

limx->1 (1/(x+1)) = 1/2.

The reason why we didn't just plug 1 in at the beginning is because the function wasn't continuous when x was 1.

8 0
3 years ago
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