Answer:
1= 4(3x+3)=3(5x+0.5)
2= x=3.5
3= 54 units
Step-by-step explanation:
thats the correct answer trust me...follow me on ig autumn.mae06
Answer:
Step-by-step explanation:
I made a table with a pretend number of years of teaching by picking a somewhat random number to start
"Clark has less seniority than Cornwall but more than Prendergast:" I picked 3 for Clark 4 for Cornwall, and 2 for Prendergast, to start.
"Prendergast has more than Brown but less than Alexander:" I see I'm running out of easy numbers here. "Prendergast has more than Brown" means give Brown 1 year but this new teacher, Alexander needs a number between Clark and Prendergast. To make room, I increased Clark and Cornwall by 1 and finished the remainder in the "Final Years" column:
<u>Teacher </u> <u>Years</u> <u> Final Years</u>
Clark 3 4
Cornwall 4 5
Prendergast 2
Brown 1
Alexander 3
The highest seniority teacher, Cornwall, is smart and refuses the job. That leaves Clark, at number 2 seniority, to become the new supervisor.
3 1/2 miles = 7/2 miles
1/2 hours= 30 minutes
So,
In 30 mins, travelled 7/2 miles
In 1 min, travelled 7/2 ÷ 30= 7/2× 1/30 = (7×1)/(2×30) = 7/60 miles
In 60 mins, travelled (7×60)/60 miles = 420/60 miles = 7 miles.
Hence, the speed is 7 miles per hour.
First translate the English phrase "Four times the sum of a number and 15 is at least 120" into a mathematical inequality.
"Four times..." means we're multiplying something by 4.
"... the sum of a number and 15..." means we're adding an unknown and 15 and then multiplying the result by 4.
"... is at least 120" means when we substitute the unknown for a value, in order for that value to be in the solution set, it can only be less than or equal to 120.
So, the resulting inequality is 4(x + 15) ≤ 120.
Simplify the inequality.
4(x + 15) ≤ 120
4x + 60 ≤ 120 <-- Using the distributive property
4x ≤ 60 <-- Subtract both sides by 60
x ≤ 15 <-- Divide both sides by 4
Now that we have the inequality in a simplified form, we can easily see that in order to be in the solution set, the variable x can be no bigger than 15.
In interval notation it would look something like this:
[15, ∞)
In set builder notation it would look something like this:
{x | x ∈ R, x ≤ 15}
It is read as "the set of all x, such that x is a member of the real numbers and x is less than or equal to 15".
