Answer: For the given reaction an increase in the forward reaction rate due to increase in the number of effective collisions.
Explanation:
According to the rate law, rate of a reaction depends on the concentration of its reactants. So, more is the number of reactants then more will be the number of collisions taking place.
As a result, more will be the amount of product formed. For example, in the reaction 
an increase in 
means an increase in the number of reactants.
Hence, more is the number of collisions taking place leading to more amount of formation of products.
Thus, we can conclude that for the given reaction an increase in the forward reaction rate due to increase in the number of effective collisions.
The answer is (2) Na2O. Considering these compounds status under room temperature. H2O is liquid. CO2 and SO2 are gas. Na2O is solid. So the Na2O has the highest melting point.
Answer:
802.2 K
Explanation:
To solve this problem we can use the formula:
Where Tb is the boiling point (in K).
We already know the values of both ΔHvap and ΔSvap, so we calculate Tb:
- ΔHvap = 47.45 kJ·mol⁻¹ = 47.45x10³J·mol⁻¹
Tb = 47.45x10³J·mol⁻¹/59.15 J·mol⁻¹·K⁻¹
So the boiling point of the compound is 802.2 K (or 529 °C)
Hi Zyshoun32,
Your Question:
When the contour lines are farther apart, is the slope more gradual or gentle.
Answer:
<u>When the slope is more gradual the farther the contour lines are.</u>
When the slope is more steeper the closer the contour lines are.
Specific heat is the amount of heat absorb or released by a substance to change the temperature to one degree Celsius. To determine the specific heat, we use the expression for the heat absorbed by the system. Heat gained or absorbed in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:
Heat = mC(T2-T1)
By substituting the given values, we can calculate for C which is the specific heat of the material.
2510 J = .158 kg ( 1000 g / 1 kg) (C) ( 61.0 - 32.0 °C)
C = 0.5478 J / g °C
