The question is incomplete, complete question is:
Study this chemical reaction:
Then, write balanced half-reactions describing the oxidation and reduction that happen in this reaction.
Oxidation:
Reduction:
Answer:
Oxidation taking place in given reaction :
Reduction taking place in given reaction;
Explanation:
Redox reaction is defined as the reaction in which oxidation and reduction reaction occur side by side.
Oxidation reaction is defined as the chemical reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.
Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.
In the given reaction, iron(II) ions are getting reduced and zinc metal is getting oxidized to zinc(II) ions.
Oxidation :
Reduction ;
Answer:
Chromosomes are structures within cells that contain a person's genes.
Explanation:
Genes are segments of deoxyribonucleic acid (DNA) that contain the code for a specific protein that functions in one or more types of cells in the body. Chromosomes are structures within cells that contain a person's genes. Genes are contained in chromosomes, which are in the cell nucleus.
Empirical formula is the simplest ratio of whole numbers of components in a compound.
Assuming for 100 g of the compound
Cu As S
mass 48.41 g 19.02 g 32.57 g
number of moles 48.41 / 63.5 g/mol 19.02 / 75 g/mol 32.57 / 32 g/mol
= 0.762 mol = 0.2536 mol = 1.018 mol
divide by the least number of moles
0.762 / 0.2536 0.2536 / 0.2536 1.018 / 0.2536
= 3.00 = 1.00 = 4.01
once they are rounded off
Cu - 3
As - 1
S - 4
therefore empirical formula is Cu₃AsS₄
Explanation:
It is given that volume is 0.50 L and molarity is 0.485 M. Hence, number of millimoles will be calculated as follows.
Number of millimoles = Molarity × Volume
As there are 1000 mL in 1 L. So, 0.50 L equals 500 mL.
Therefore, putting the given values into the above formula as follows.
Number of millimoles = Molarity × Volume
= 0.485 M × 500 mL
= 242.5
Thus, we can conclude that 242.5 millimoles of copper(II) sulfate has been added by the chemist to the flask.
