Question

The ΔHvap of a certain compound is 47.45 kJ·mol−1 and its ΔSvap is 59.15 J·mol−1·K−1. What is the boiling point of this compound?

Answer 1

Answer:

802.2 K

Explanation:

To solve this problem we can use the formula:

• Tb = ΔHvap / ΔSvap

Where Tb is the boiling point (in K).

We already know the values of both ΔHvap and ΔSvap, so we calculate Tb:

• ΔHvap = 47.45 kJ·mol⁻¹ = 47.45x10³J·mol⁻¹

Tb = 47.45x10³J·mol⁻¹/59.15 J·mol⁻¹·K⁻¹

• Tb = 802.2 K

So the boiling point of the compound is 802.2 K (or 529 °C)