Answer:
1: x = -1
2: x = 3
3: x = -3
Step-by-step explanation:
f(x)=<u>x^3+x^2</u>−9x−9
f(x)=x^2<u>(</u>x+1) <u>−9x−9</u>
f(x) = x^2<u>(x+1)</u> - 9<u>(x+1)</u>
f(x)= (x+1)<u>(x^2-9)</u>
f(x) =(x+1)(x-3)(x+3)
Answer:
d = 
Step-by-step explanation:
Given that W varies jointly as L and d² then the equation relating them is
W = kLd² ← k is the constant of variation
To find k use the condition W = 140 when d = 4 and L = 54, thus
140 = k × 54 × 4² = 864k ( divide both sides by 864 )
= k , that is
k = 
W = Ld² ← equation of variation
Multiply both sides by 216
216W = 35Ld² ( divide both sides by 35L )
= d² ( take the square root of both sides )
d =
Ok so if you did 156-6 (considering it was 6 more you want to subtract it) and then because the girls was doubled the boys (you are now at 150) you must divide that by 3 which will give you 50. But you need to double it (for girls) which is 100 and then you have 50 left over which is for the boys. Boys=50 girls=106
1.
the x value of the vertex in form
ax^2+bx+c=y
is
-b/2a
so
-2x^2+8x-18
x value of vertex is
-8/(2*-2)=-8/-4=2
plug it in to get y value
-2(2)^2+8(2)-18
-2(4)+16-18
-8-2
-10
vertex is at (2,-10)
or you could complete the square to get into y=a(x-h)^2+k, where the vertex is (h,k)
so as follows
y=(-2x^2+8x)-18
y=-2(x^2-4x)-18
y=-2(x^2-4x+4-4)-18
y=-2((x-2)^2-4)-18
y=-2(x-2)^2+8-18
y=-2(x-2)^2-10
vertex is (2,-10)
5.
vertex is the time where the speed is the highest
at about t=10, the speed is at its max
