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3 years ago

Can you help me pls lol I’m doing a test

Mathematics

1 answer:

Schach [20]3 years ago

6 0

Answer:

Dont say your doing a test, brainly is strict and will delete your question because its timed

Step-by-step explanation:

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The process of paying off the principal on the loan is called a(n) _.

NISA [10]

The answer is amortization

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4 years ago

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Fill in the missing numbers in these equation <br> (-2) . (-4.5)= ? <br> ?=

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Multiplying two negatives makes it positive.

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3 years ago

Which values for A and B will create infinitely many solutions for this system of equations? Ax-y=8 2x+y=B plss hurry im being t

Lynna [10]

Answer:

A=-2

B=-8

Step-by-step explanation:

In order for the system of linear equations to have infinitely many solution, they must be the same equation.

Ax-y=8

2x+y=B

We need to choose A and B so they are the same equation.

I notice they are both in the same form but in the second column you have opposites;

the -y and y.

So im going to multiply either equation by -1 so that part is exactly the same.

Don't choose both; choose only one.

Let's multiply the first equation by -1.

Doing this gives us the following:

-Ax+y=-8

2x+y=B

So now we can choose A and B so these equations appear exactly the same.

We need -A=2 and B=-8.

-A=2 implies A=(opposite of 2) which is -2.

Conclusion:

A=-2

B=-8

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3 years ago

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Find the perimeter of the pentagon MNPQR with vertices M(2, 4), N(5, 8), P(8, 4), Q(8, 1), and R(2, 1)

Gekata [30.6K]

Answer:

The pentagon MNPQR has a perimeter of 22 units.

Step-by-step explanation:

Geometrically speaking, the perimeter of the pentagon is the sum of the lengths of each side, that is:

$p = MN + NP + PQ + QR + RM$ (1)

$p = \sqrt{\overrightarrow{MN}\,\bullet \, \overrightarrow{MN}} + \sqrt{\overrightarrow{NP}\,\bullet \, \overrightarrow{NP}} + \sqrt{\overrightarrow{PQ}\,\bullet \, \overrightarrow{PQ}} + \sqrt{\overrightarrow{QR}\,\bullet \, \overrightarrow{QR}} + \sqrt{\overrightarrow{RM}\,\bullet \, \overrightarrow{RM}}$ (1b)

If we know that $M(x,y) = (2,4)$ , $N(x,y) = (5,8)$ , $P(x,y) = (8,4)$ , $Q(x,y) = (8,1)$ and $R(x,y) = (2,1)$ , then the perimeter of the pentagon MNPQR is:

$p =\sqrt{(5-2)^{2}+(8-4)^{2}} + \sqrt{(8-5)^{2}+(4-8)^{2}}+\sqrt{(8-8)^{2}+(1-4)^{2}}+\sqrt{(2-8)^{2}+(1-1)^{2}}+\sqrt{(2-2)^{2}+(4-1)^{2}}$ $p = \sqrt{3^{2}+4^{2}} + \sqrt{3^{2}+(-4)^{2}}+\sqrt{0^{2}+(-3)^{2}}+\sqrt{(-6)^{2}+0^{2}}+\sqrt{0^{2}+3^{2}}$