Hi there!
The two trapezoids are similar, so we can determine a common scale factor:
OL/UR = NM/TS
9/3 = 6/2
3 = 3
Trapezoid ONML is 3x larger than UTSR, so:
RS = 4, LM = y
3RS = LM
3 · 4 = y = 12.
Find x using the same method:
3UT = ON
3(2x+1) = 4x + 9
6x + 3 = 4x + 9
2x = 6
x = 3.
Answer:
See attachment
Step-by-step explanation:
We want to graph the line with slope
and y-intercept ,
The equation of this line is
Starting at -7 on the y-axis, we run 5 units and rise 2 units right.
Then draw a line through the y intercept and the new point
The graph is shown in the attachment.
The tangent or tanθ in a right-angle triangle is the ratio of its perpendicular to its base. The distance from point C to point D is 258.8 meters.
<h3>What is Tangent (Tanθ)?</h3>The tangent or tanθ in a right-angle triangle is the ratio of its perpendicular to its base. it is given as,
where,
θ is the angle,
Perpendicular is the side of the triangle opposite to the angle θ,
The base is the adjacent smaller side of the angle θ.
The distance from point C to D is equal to the distance from point A to B. Therefore, the height of the building can be written as,
Tan(25°) = AB / BC
Tan(25°) × 555 m = AB
AB = 258.8 meters
Hence, the distance from point C to point D is 258.8 meters.
Learn more about Tangent (Tanθ):
#SPJ1