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Reil [10]
3 years ago
5

Does anyone know this one

Mathematics
1 answer:
yawa3891 [41]3 years ago
5 0

It's A. if a = b, then a^2 = b^2

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A team had 7 wins and 2 losses. What is the percentage of wins?
Yakvenalex [24]

Answer:

78%

Step-by-step explanation:

Total matches=7+2=9

Total wins=7

Percentage of wins=matches won/total matches * 100

= 7/9*100

=77.8%

≈78%

5 0
3 years ago
if im learning a language and want to be able to master it in a year what is a good way to reach my goal without help and withou
Diano4ka-milaya [45]

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4 0
4 years ago
Forces with magnitudes of 2000 newtons and 900 newtons act on a machine part at angles of +30degrees and -45degrees respectively
mote1985 [20]

To get the resultant magnitude and direction of the forces we need to separate the force into its x and y components. For the x components it is the sum of 2000cos(30) and 900cos(45), which is 2368.4469 N. For the y components it will be the sum of 2000sin(30) and -900sin(45), the value for the second force is negative because it is pointing downwards, their sum would be 363.6038 N. The magnitude for the resultant force can be determined using the pythagorean theorem R=sqrt(2368.4469^2 + 363.6038^2) while its direction is found using tan^-1(363.6038/2368.4469). The final answer would be 2396.1946 N with an angle of 8.7279 degrees from the right side of x axis.




3 0
3 years ago
What is the equation of the line, in slope-intercept form, that passes through (3, -1) and (-1, 5)?
Mademuasel [1]

just use thus (Y2-Y1)/(X2-X1)

6 0
4 years ago
156 people said they spent the night in Wal-Mart the night before Black Friday to get the good deals! This number represented 39
Musya8 [376]

Answer: 400 Shoppers

Step-by-step explanation:

Given

156 people spent the night in Wal-mart

These 156 people represent 39% of total shoppers at Wal-mart

Suppose x is the total no of shoppers at Wal-mart

So, we can write

\Rightarrow 39\%\ \text{of}\ x=156\\\Rightarrow 0.39\times x=156\\\\\Rightarrow x=\dfrac{156}{0.39}=400\ \text{People}

6 0
3 years ago
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