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hammer [34]
3 years ago
9

Plz help ASAP!!!!!!!!​

Mathematics
1 answer:
lilavasa [31]3 years ago
4 0

Answer:

The answer is 95.03

Step-by-step explanation

The formula that I used

A=πr^2

Area  = π·5.5^2 ≈ 95.03318

Hope that helps :)

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The sum of two numbers is eighteen. The total of three times the smaller and twice the larger is forty-four. Find the two number
sashaice [31]

Answer:

  • The numbers are 8 and 10.

Step-by-step explanation:

Let the numbers be x and y.

The sum of two numbers is eighteen:

  • x + y = 18

The total of three times the smaller and twice the larger is forty-four:

  • 3x + 2y = 44

Solve the system by substitution:

  • x = 18 - y

Substitute x and solve for y:

  • 3(18 - y) + 2y = 44
  • 54- 3y + 2y = 44
  • 54 - y = 44
  • y = 54 - 44
  • y = 10

Find x:

  • x = 18 - 10
  • x = 8
6 0
1 year ago
SIMPLE INTEREST
cupoosta [38]
The answer would be 5 years. I=PxRxT.
3 0
3 years ago
Read 2 more answers
Juan works at bob’s appliance store . he earns $400 per week he also receives a commission of $50 for each appliance he sels
sweet-ann [11.9K]

Answer:

400×W+50×A=?

Step-by-step explanation:

since it's 400 a week then you need to take into account the weeks worked. Then since it's 50 per an appliance you need to multiply by the number sold.

5 0
3 years ago
Solve (x-3)^2 = 5 HELP ASAP!!! Please!! :(
Bas_tet [7]

Answer:

<em>Answer</em><em> </em><em>is</em><em> </em><em>option</em><em> </em><em>d</em><em> </em>

Step-by-step explanation:

given \: expression \: is \:  {(x - 3)}^{2}  = 5 \\  {x}^{2}  - 6x + 9 = 5 \\ subtracting \: 5 \: on \: both \: sides \: we \: get \\  {x}^{2}  - 6x + 4 = 0 \\ on \: solving \: the \: quadratic \: equation \: by \\  \: completing \: square \: method \\  {x}^{2}  - 6x =  - 4 \\ adding \:  {3}^{2} on \: both \: sides \: w e\: get \\  {x}^{2}  - 6x +  {3}^{2}  =  {3}^{2}  - 4 \\  {(x - 3)}^{2} = 5 \\ x - 3 + =    \sqrt{5}  \\ x =  \sqrt{5 }  + 3

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

5 0
2 years ago
A 1.5-mm layer of paint is applied to one side of the following surface. Find the approximate volume of paint needed. Assume tha
Mariulka [41]

Answer:

V = 63π / 200  m^3

Step-by-step explanation:

Given:

- The function y = f(x) is revolved around the x-axis over the interval [1,6] to form a spherical surface:

                                 y = √(42*x - x^2)

- The surface is coated with paint with uniform layer thickness t = 1.5 mm

Find:

The volume of paint needed

Solution:

- Let f be a non-negative function with a continuous first derivative on the interval [1,6]. The Area of surface generated when y = f(x) is revolved around x-axis over the interval [1,6] is:

                           S = 2*\pi \int\limits^a_b { [f(x)*\sqrt{1 + f'(x)^2} }] \, dx

- The derivative of the function f'(x) is as follows:

                            f'(x) = \frac{21-x}{\sqrt{42x-x^2} }

- The square of derivative of f(x) is:

                            f'(x)^2 = \frac{(21-x)^2}{42x-x^2 }

- Now use the surface area formula:

                           S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2} *\sqrt{1 + \frac{(21-x)^2}{42x-x^2 } }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2+(21-x)^2} }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2+441-42x+x^2} }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{441} }] \, dx\\S = 2*\pi \int\limits^6_1 { 21} \, dx\\\\S = 42*\pi \int\limits^6_1 { dx} \,\\\\S = 42*\pi [ 6 - 1 ]\\\\S = 42*5*\pi \\\\S = 210\pi

- The Volume of the pain coating is:

                           V = S*t

                           V = 210*π*3/2000

                          V = 63π / 200 m^3

8 0
3 years ago
Read 2 more answers
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