Prove cos a = 5/13 pls solve it and no link pls..........
1 answer:
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Answer:
vertex = (- 1, 3 )
Step-by-step explanation:
Given a parabola in standard form
y = ax² + bx + c ( a ≠ 0 )
Then the x- coordinate of the vertex is
= -
y = 2x² + 4x + 5 ← is in standard form
with a = 2, b = 4, then
= -
= - 1
Substitute x = - 1 into the equation for corresponding value of y, that is
y = 2(- 1)² + 4(- 1) + 5 = 2 - 4 + 5 = 3
vertex = (- 1, 3 )