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Mkey [24]
3 years ago
15

I need the answer fast pls

Mathematics
2 answers:
puteri [66]3 years ago
7 0

Answer:

58

Step-by-step explanation:

The median in a box plot is the line in the middle of the box

The median is 58

Montano1993 [528]3 years ago
6 0

Answer:

58

Step-by-step explanation:

The median in a box plot is the line in the middle of the box

The median is 58

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Is (2, 2) a solution of y &lt; 4x - 6?<br> Choose 1 answer<br> yes or no
zalisa [80]

No, (2,2) is not solution of y < 4x - 6

Step-by-step explanation:

To solve above linear problem, we use standard method of  Back- Substitution.

First of all, A point (2,2) only becomes solution of equation, if it satisfies equation y < 4x - 6.

Here, the  y < 4x - 6  seems to be like a linear equation.

In this Equation, using  Back- Substitution method,

Point (2,2) : first digit 2 corresponds to x- coordinate and second digit 2 corresponds to y-coordinate.

           y < 4x - 6.....(1)     \\\         x= 2        .....(2)       \\\       y= 2        .....(3)

By putting value of x and y in equation (1),

Equation becomes,

        2 <  4 \times 2  - 6

       2 < 8       -  6

       2 <  2      .... not true mathematically.

Finally, the result came is not true. Therefore, (2,2) is not solution for equation

y < 4x - 6          

4 0
3 years ago
What is the area of the trapezoid below?
TEA [102]
The answer is A. 36\sqrt{3} cm^{2}
3 0
3 years ago
Read 2 more answers
The fraction: 340 | 3/4
Effectus [21]

Answer:

It's A I hope that helps

Step-by-step explanation:

8 0
3 years ago
The diagram shows the arcs for the construction of —
babunello [35]
Can u show the picture?
3 0
3 years ago
For what value of constant c is the function k(x) continuous at x = 0 if k =
nlexa [21]

The value of constant c for which the function k(x) is continuous is zero.

<h3>What is the limit of a function?</h3>

The limit of a function at a point k in its field is the value that the function approaches as its parameter approaches k.

To determine the value of constant c for which the function of k(x)  is continuous, we take the limit of the parameter as follows:

\mathbf{ \lim_{x \to 0^-} k(x) =  \lim_{x \to 0^+} k(x) =  0 }

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}= c }

Provided that:

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}= \dfrac{0}{0} \ (form) }

Using l'Hospital's rule:

\mathbf{\implies  \lim_{x \to 0} \ \  \dfrac{\dfrac{d}{dx}(sec \ x - 1)}{\dfrac{d}{dx}(x)}=  \lim_{x \to 0}   sec \ x  \ tan \ x = 0}

Therefore:

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}=0 }

Hence; c = 0

Learn more about the limit of a function x here:

brainly.com/question/8131777

#SPJ1

5 0
2 years ago
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