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Feliz [49]
2 years ago
12

Help ill give brainliest 9 − 3z + 4 + 6z − 2 = ______

Mathematics
2 answers:
Phoenix [80]2 years ago
5 0

Answer:

<h2><u>[B] 11 + 3z</u></h2>

Explanation:

9 − 3z + 4 + 6z − 2

  • <u>Group Like Terms</u>

-3z + 6z + 9 + 4 - 2

  • <u>Add Similar Elements: -3z + 6z = 3z</u>

3z + 9 + 4 - 2

  • <u>Add / Subtract: 9 + 4 - 2 = 11</u>
<h2><u>3z + 11</u></h2>
Lyrx [107]2 years ago
3 0

Answer:

11+3z

Step-by-step explanation:

You would combine the like terms, 9+4-2 is 11 and 6z-3z=3z

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Mrs. Hernandez earns $35.60 per hour and in one week earned $854.40. For how many hours did she work last week? What expression
zmey [24]

Answer:

Option A

Step-by-step explanation:

Given the following question:
Mrs. Hernandez earns $35.60 an hour
One week she earned $854.40

To find the answer we divide 8,544 by 356

8544\div356=24
854.40\div35.60=24

Mrs. Hernandez worked "24 hours last week" by using the first options equation, we can find that answer.

Hope this helps.

4 0
2 years ago
Each floor has r rooms. On 8 floors, there are a total of 256 rooms. Wrongs an equation to represent this situation
ExtremeBDS [4]

Answer: 8r = 256

Step-by-step explanation:

3 0
3 years ago
To mix weed killer with water correctly, it is necessary to mix 30 teaspoons of weed killer with 5 gallons of water. Find how ma
nlexa [21]
Answer
6 Gallons



Each gallon of water needs 6 teaspoons because 30/5=6

Now we know that teaspoons/6=amount of gallons

36/6=6 gallons
7 0
2 years ago
Prove that the diagonals of a parallelogram bisect each other​
Nady [450]

Answer:

[ See the attached picture ]

The diagonals of a parallelogram bisect each other.

✧ Given : ABCD is a parallelogram. Diagonals AC and BD intersect at O.

✺ To prove : AC and BD bisect each other at O , i.e AO = OC and BO = OD.

Proof :\begin{array}{ |c| c |  c |  } \hline \tt{SN}& \tt{STATEMENTS} & \tt{REASONS}\\ \hline 1& \sf{In  \: \triangle ^{s}  \:AOB \: and \: COD  } \\  \sf{(i)}&  \sf{ \angle \: OAB =  \angle \: OCD\: (A)}& \sf{AB \parallel \: DC \: and \: alternate \: angles} \\  \sf{(ii)} &\sf{AB = DC(S)}& \sf{Opposite \: sides \: of \: a \: parallelogram} \\  \sf{(iii)} &\sf{ \angle \: OBA=  \angle \: ODC(A)} &\sf{AB \parallel \:DC \: and \: alternate \: angles} \\  \sf{(iv)}& \sf{ \triangle \:AOB\cong \triangle \: COD}& \sf{A.S.A \: axiom}\\ \hline 2.& \sf{AO = OC \: and \: BO = OD}& \sf{Corresponding \: sides \: of \: congruent \: triangle}\\ \hline 3.& \sf{AC \: and \: BD \: bisect \: each \: other \: at \: O}& \sf{From \: statement \: (2)}\\ \\ \hline\end{array}.          Proved ✔

♕ And we're done! Hurrayyy! ;)

# STUDY HARD! So, Tomorrow you can answer people like this , " Dude , I just bought this expensive mobile phone but it is not that expensive for me" [ - Unknown ] :P

☄ Hope I helped! ♡

☃ Let me know if you have any questions! ♪

\underbrace{ \overbrace  {\mathfrak{Carry \: On \: Learning}}} ☂

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

5 0
3 years ago
Solve for m. -5&lt;3+m
Firlakuza [10]

-5 < 3 + m      <em>subtract 3 from both sides</em>

-5 - 3 < 3 - 3 + m

-8 < m → m > -8

8 0
3 years ago
Read 2 more answers
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