Randy made 64 ballon animals and her sister made 32 ballon animals
<em><u>Solution:</u></em>
Let the number of ballon animals sold by Randi be "x"
Let the number of ballon animals sold by her sister be "y"
Cost of 1 ballon animal = $ 0.50
<em><u>Rando made twice as many animals as her sister</u></em>
Number of ballon animals sold by Randi = twice the number of ballon animals sold by her sister
x = 2y ---- eqn 1
<em><u>Together, they earned $ 48</u></em>
Therefore, we can frame a equation as:
Number of ballon animals sold by Randi x Cost of 1 ballon animal + number of ballon animals sold by her sister x Cost of 1 ballon animal = 48


<em><u>Therefore, from eqn 1</u></em>
x = 2y
x = 2(32)
x = 64
Thus Randy made 64 ballon animals and her sister made 32 ballon animals