Answer:
16, 8, and 36
Step-by-step explanation:
brainliest pls :)
I hope this helps you
1)
B=D
A=X
4x-20=3x-11
4x-3x=20-11
x=9
4x-20+C=180
4.9-20+C=180
C=180-16
C=164
2)
L=M
M+J=180
2x+10+18x+10=180
20x=160
x=8
M=2.8+10=26
J=18.8+10=154
K+J =180
K+154=180
K=26
Answer:
Average rate of change=\displaystyle \frac{\text{Change in output}}{\text{Change in input}}
Change in input
Change in output
=\displaystyle \frac{\Delta y}{\Delta x}
Δx
Δy
=\displaystyle \frac{{y}_{2}-{y}_{1}}{{x}_{2}-{x}_{1}}
x
2
−x
1
y
2
−y
1
=\displaystyle \frac{f\left({x}_{2}\right)-f\left({x}_{1}\right)}{{x}_{2}-{x}_{1}}
x
2
−x
1
f(x
2
)−f(x
1
)
The answer is 238.5
hopes this helps
Answer:
Given:You sample 160 men, and 25% own cats
You sample 120 women, and 20% own cats.
To Find : Find the test statistic, rounded to two decimal places.
Solution:
You sample 160 men, and 25% own cats.
No. of men have cats = ![\frac{25}{100} \times 160](https://tex.z-dn.net/?f=%5Cfrac%7B25%7D%7B100%7D%20%5Ctimes%20160)
= ![40](https://tex.z-dn.net/?f=40)
So, ![n_1=160 , y_1=40](https://tex.z-dn.net/?f=n_1%3D160%20%2C%20y_1%3D40)
You sample 120 women, and 20% own cats.
No. of women have cats = ![\frac{20}{100} \times 120](https://tex.z-dn.net/?f=%5Cfrac%7B20%7D%7B100%7D%20%5Ctimes%20120)
= ![24](https://tex.z-dn.net/?f=24)
So, ![n_2=120 , y_2=24](https://tex.z-dn.net/?f=n_2%3D120%20%2C%20y_2%3D24)
We will use Comparing Two Proportions
![\widehat{p_1}=\frac{y_1}{n_1}](https://tex.z-dn.net/?f=%5Cwidehat%7Bp_1%7D%3D%5Cfrac%7By_1%7D%7Bn_1%7D)
![\widehat{p_1}=\frac{40}{160}](https://tex.z-dn.net/?f=%5Cwidehat%7Bp_1%7D%3D%5Cfrac%7B40%7D%7B160%7D)
![\widehat{p_1}=0.25](https://tex.z-dn.net/?f=%5Cwidehat%7Bp_1%7D%3D0.25)
![\widehat{p_2}=\frac{y_2}{n_2}](https://tex.z-dn.net/?f=%5Cwidehat%7Bp_2%7D%3D%5Cfrac%7By_2%7D%7Bn_2%7D)
![\widehat{p_2}=\frac{24}{120}](https://tex.z-dn.net/?f=%5Cwidehat%7Bp_2%7D%3D%5Cfrac%7B24%7D%7B120%7D)
![\widehat{p_2}=0.2](https://tex.z-dn.net/?f=%5Cwidehat%7Bp_2%7D%3D0.2)
Let
and
be the probabilities of men having cat and women having cat receptively
![H_0:p_1=p_2\\H_a:p_1](https://tex.z-dn.net/?f=H_0%3Ap_1%3Dp_2%5C%5CH_a%3Ap_1%3Cp_2)
![\widehat{p}=\frac{y_1+y_2}{n_1+n_2} =\frac{24+40}{160+120}=0.228](https://tex.z-dn.net/?f=%5Cwidehat%7Bp%7D%3D%5Cfrac%7By_1%2By_2%7D%7Bn_1%2Bn_2%7D%20%3D%5Cfrac%7B24%2B40%7D%7B160%2B120%7D%3D0.228)
Formula of test statistic : ![\frac{\widehat{p_1}-\widehat{p_2}}{\sqrt{\widehat{p}(1-\widehat{p})(\frac{1}{n_1}+\frac{1}{n_2})}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cwidehat%7Bp_1%7D-%5Cwidehat%7Bp_2%7D%7D%7B%5Csqrt%7B%5Cwidehat%7Bp%7D%281-%5Cwidehat%7Bp%7D%29%28%5Cfrac%7B1%7D%7Bn_1%7D%2B%5Cfrac%7B1%7D%7Bn_2%7D%29%7D%7D)
Substitute the values
test statistic : ![\frac{0.25-0.2}{\sqrt{0.228(1-0.228)(\frac{1}{160}+\frac{1}{120})}}](https://tex.z-dn.net/?f=%5Cfrac%7B0.25-0.2%7D%7B%5Csqrt%7B0.228%281-0.228%29%28%5Cfrac%7B1%7D%7B160%7D%2B%5Cfrac%7B1%7D%7B120%7D%29%7D%7D)
test statistic : ![0.986](https://tex.z-dn.net/?f=0.986)
So, test statistic is 0.986