Answer:
I think its C if I’m wrong sorry
Step-by-step explanation:
Answer:
88
Step-by-step explanation:
Write the expression for the sum in the relation you want.
Sn = u1(r^n -1)/(r -1) = 2.1(1.06^n -1)/(1.06 -1)
Sn = (2.1/0.06)(1.06^n -1) = 35(1.06^n -1)
The relation we want is ...
Sn > 5543
35(1.06^n -1) > 5543 . . . . substitute for Sn
1.06^n -1 > 5543/35 . . . . divide by 35
1.06^n > 5578/35 . . . . . . add 1
n·log(1.06) > log(5578/35) . . . take the log
n > 87.03 . . . . . . . . . . . . . . divide by the coefficient of n
The least value of n such that Sn > 5543 is 88.
X=â^'7 I think. im not sure if that's right tho
Answer:
x = 3.162
Step-by-step explanation:
Your first step is to get x by itself by subtracting 3 from both sides.
3-
= -7
-
= -10
Now multiply by both sidex by -1 to make x positive.
= 10
now take the square root of both sides.
= 
x = 
x = 3.162