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aleksandr82 [10.1K]
3 years ago
5

How many Oxygen atoms are in 2NA(OH)3

Chemistry
2 answers:
Dmitry [639]3 years ago
4 0

Answer:

3 oxygen atom

hope it helps.

leva [86]3 years ago
3 0

Answer:

Explanation:

There are 3 oxygen atoms.

<h3>have a nice day!</h3>

<u><em>Can you choose me brainliest?</em></u>

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a solution is made by dissolving cadmium fluoride (CdF2 Ksp =6.44×10 −3 ) in 100.0 mL of water until excess solid is present. So
Lunna [17]

Answer:

Answers are in the explanation

Explanation:

Ksp of CdF₂ is:

CdF₂(s) ⇄ Cd²⁺(aq) + 2F⁻(aq)

Ksp = 6.44x10⁻³ = [Cd²⁺] [F⁻]²

When an excess of solid is present, the solution is saturated, the molarity of Cd²⁺ is X and F⁻ 2X:

6.44x10⁻³ = [X] [2X]²

6.44x10⁻³ = 4X³

X = 0.1172M

<h3>[F⁻] = 0.2344M</h3><h3 />

Ksp of LiF is:

LiF(s) ⇄ Li⁺(aq) + F⁻(aq)

Ksp = 1.84x10⁻³ = [Li⁺] [F⁻]

When an excess of solid is present, the solution is saturated, the molarity of Li⁺ and F⁻ is XX:

1.84x10⁻³ = [X] [X]

1.84x10⁻³ = X²

X = 0.0429

<h3>[F⁻] = 0.0429M</h3><h3 /><h3>The solution of CdF₂ has the higher fluoride ion concentration</h3>
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3 years ago
Explain why iron structures need protection from corrosion while aluminium structures do not?
KiRa [710]
<span>Because aluminium oxide is strong and forms a coating over itself, but iron oxide (rust) will flake away.</span>
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Jack tries to place magnets on the door of his refrigerator. He observes that the magnets don't stick. He guesses that the door
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B. Construct a hypothesis

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How many kilojoules of energy would be required to heat a 225g block of aluminum from 23.0 C to 73.5 C?
gulaghasi [49]

Answer:

\boxed {\boxed {\sf 10.2 \ kJ}}

Explanation:

We are asked to find how many kilojoules of energy would be required to heat a block of aluminum.

We will use the following formula to calculate heat energy.

q=mc \Delta T

The mass (m) of the aluminum block is 225 grams and the specific heat (c) is 0.897 Joules per gram degree Celsius. The change in temperature (ΔT) is the difference between the final temperature and the initial temperature.

  • ΔT = final temperature - inital temperature

The aluminum block was heated from 23.0 °C to 73.5 °C.

  • ΔT= 73.5 °C - 23.0 °C = 50.5 °C

Now we know all three variables and can substitute them into the formula.

  • m= 225 g
  • c= 0.897 J/g° C
  • ΔT= 50.5 °C

q= (225 \ g )(0.897 \ J/g \textdegree C)(50.5 \textdegree C)

Multiply the first two numbers. The units of grams cancel.

q= (225 \ g  * 0.897 \ J/g \textdegree C)(50.5 \textdegree C)

q= (225   * 0.897 \ J / \textdegree C)(50.5 \textdegree C)

q= (201.825\ J / \textdegree C)(50.5 \textdegree C)

Multiply again. This time, the units of degrees Celsius cancel.

q= 201.825 \ J * 50.5

q= 10192.1625 \ J

The answer asks for the energy in kilojoules, so we must convert our answer. Remember that 1 kilojoule contains 1000 joules.

\frac { 1  \ kJ}{ 1000 \ J}

Multiply by the answer we found in Joules.

10192.1625 \ J * \frac{ 1 \ kJ}{ 1000 \ J}

10192.1625  * \frac{ 1 \ kJ}{ 1000 }

\frac {10192. 1625}{1000} \ kJ

10.1921625 \ kJ

The original values of mass, temperature, and specific heat all have 3 significant figures, so our answer must have the same. For the number we found, that is the tneths place. The 9 in the hundredth place tells us to round the 1 up to a 2.

10.2 \ kJ

Approximately <u>10.2 kilojoules</u> of energy would be required.

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What is sodium used for
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Answer:

sodium is used as heat exchanger in some nuclear reactions

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