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3 years ago

The solubility of two slightly soluble salts of M^2+ , MA and MZ_2, are the same, 4 x 10^â4 mol/L.

Chemistry

1 answer:

LekaFEV [45]3 years ago

7 0

Answer:

a) MZ₂

b) They have the same concentration

c) 4x10⁻⁴ mol/L

Explanation:

a) The solubility (S) is the concentration of the salt that will be dissociated and form the ions in the solution, the solubility product constant (Kps) is the multiplication of the concentration of the ions elevated at their coefficients. The concentration of the ions depends on the stoichiometry and will be equivalent to S.

The salts solubilization reactions and their Kps values are:

MA(s) ⇄ M⁺²(aq) + A⁻²(aq) Kps = S*S = S²

MZ₂(aq) ⇄ M⁺²(aq) + 2Z⁻(aq) Kps = S*S² = S³

Thus, the Kps of MZ₂ has a larger value.

b) A saturated solution is a solution that has the maximum amount of salt dissolved, so, the concentration dissolved is solubility. As we can notice from the reactions, the concentration of M⁺² is the same for both salts.

c) The equilibrium will be not modified because the salts have the same solubility. So, let's suppose that the volume of each one is 1 L, so the number of moles of the cation in each one is 4x10⁻⁴ mol. The total number of moles is 8x10⁻⁴ mol, and the concentration is:

8x10⁻⁴ mol/2 L = 4x10⁻⁴ mol/L.

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Which is a method that can be used to separate the components of a solution?

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Answer:

distillation

Explanation:

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3 years ago

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How many molecules of CH4 are in 48.2 g of this compound? A) 2.00 x 1023 B) 5.00 x 10-24 C)1.81 x 1024 D) 4.00 E) 4.64 x 1026 10

Tasya [4]

Answer: The correct answer is Option C.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of methane = 48.2 g

Molar mass of methane = 16 g/mol

Putting values in above equation, we get:

$\text{Moles of }CH_4=\frac{48.2g}{16g/mol}=3.0125mol$

According to mole concept:

1 mole of compound contains $6.022\times 10^{23}$ number of molecules.

So, 3.0125 moles of methane will contain = $3.0125\times 6.022\times 10^{23}18.141\times 10^{23}=1.81\times 10^{24}$ number of molecules.

Hence, the correct answer is Option C.

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3 years ago

If a gas occupies 4600 mL at 0.9 atm and 195°C, what is the new volume in ml

Bumek [7]

Answer:

The new volume is 2415 mL

Explanation:

The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases.

Boyle's law says that the volume occupied by a given gas mass at constant temperature is inversely proportional to the pressure and is expressed mathematically as:

P * V = k

Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

$\frac{V}{T} =k$

Gay-Lussac's law indicates that when there is a constant volume, as the temperature increases, the gas pressure increases. And when the temperature is decreased, the gas pressure decreases. This can be expressed mathematically in the following way:

$\frac{P}{T} =k$

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

$\frac{P*V}{T} =k$

Having two different states, an initial state and an final state, it is true:

$\frac{P1*V1}{T1} =\frac{P2*V2}{T2}$

In this case:

P1= 0.9 atm
V1=4,600 mL= 4.6 L (being 1 L=1,000 mL)
T1= 195 °C= 468 °K (being 0°C=273°K)

The final state 2 is in STP conditions:

P2= 1 atm
V2= ?
T2= 0°C= 273 °K

Replacing:

$\frac{0.9 atm*4.6L}{468K} =\frac{1 atm*V2}{273K}$

Solving:

$V2=\frac{0.9 atm*4.6L}{468K}*\frac{273K}{1 atm}$

V2= 2.415 L =2,415 mL

The new volume is 2415 mL

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3 years ago

For each solute identify the better solvent: water or carbon tetrachloride Na2, I2, CCH2O, C6H6

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C6H14 = CCl4 (C6H14 won't mix with water at all)
Na2S = water (Na2S is a salt. Salts dissolve best in water)
Br2 = CCl4, but it will also dissolve in water.

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3 years ago

If element X has 59 protons, how many electrons does it have?

laiz [17]

If element X has 59 protons then element X has 59 electrons.

Side note: as long as an element stays an atom the number of protons and electrons will always have the same value.

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3 years ago