The Lewis structures in which there are no formal charges is the most stable. Hence, structure (b) is the more stable form of FNO2.
<h3>Lewis structure</h3>
The question is incomplete but I will try to answer you as much as I can. Now the equation is missing hence we can't numerically caculate the enthalpy chnage of the reaction from bond energies. However, we can do this using the formula; Σbond energy of reactants - bond energy of products.
Concerning the Lewis structures of FNO2, the most stable structure is structure (b) as shown in the image attached where the atoms have no formal charges.
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The answer is chemical weathering .
The molarity of the dilution solution is 0.050 M
<h3>Further explanation</h3>
Molarity is a way to express the concentration of the solution
Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution
Where
M = Molarity
n = Number of moles of solute
V = Volume of solution
Dilution formula :
M₁=6 M
V₁=12.5 ml
V₂=1.5 L=1500 ml
Answer:
1.69×10²⁹ molecules.
Explanation:
The following data were obtained from the question:
Mass of Ammonia (NH3) = 5.25 tons
Molecules of Ammonia (NH3) =.?
Next, we shall convert 5.25 tons to grams (g). This can be obtained as follow:
1 ton = 907184.74 g
Therefore,
5.25 ton = 5.25 ton × 907184.74 g / 1 ton
5.25 ton = 4762719.885 g
Therefore, 5.25 tons is equivalent to 4762719.885 g
Finally, we shall determine the number of molecules of ammonia, NH3 in 4762719.885 g. This can be obtained as follow:
From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ molecules. This implies that 1 mole of ammonia, NH3 also contains 6.02×10²³ molecules.
1 mole of ammonia, NH3 = 14 + (3x1) = 14 + 3 = 17 g
17 g of ammonia, NH3 contains 6.02×10²³ molecules.
Therefore, 4762719.885 g of ammonia, NH3 will contain = (4762719.885 × 6.02×10²³) / 17 = 1.69×10²⁹ molecules.
From the calculations made above,
5.25 tons (4762719.885 g) of ammonia, NH3 contains 1.69×10²⁹ molecules.
The theoretical yield of Li3N is 20.9 g .
