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Shtirlitz [24]
4 years ago
6

At 8 a.m. the temperature was -2f at 1 pm the temperature was 12f warmer.

Mathematics
1 answer:
dybincka [34]4 years ago
4 0

Answer:

The function for the temperature is:

T(t) = 2.4t - 2

Step-by-step explanation:

This problem can be modeled by a first order equation in the following format:

T(t) = at + b

Using what the problem stated, we can build a system to mode the temperature.

Building the function:

The problem states that at 8 a.m. the temperature was -2f. To make the solution easier, I am going to say that 8 a.m. is the zero hour. So T(0) = -2. It means that when t = 0, T(t) = -2. With this, we can find the value of b in the function to determine the temperature.

T(t) = at + b

-2 = a*(0) + b

b = -2

Now we have that

T(t) = at - 2

The problem also states that at 1 pm the temperature was 12f warmer. 12f warmer is -2+12 = 10f. 1 p.m. is five hours from 8 a.m., so T(5) = 10. We can substitute in the equation to find the value of a:

T(t) = at - 2

10 = a*(5) - 2

5a = 12

a = \frac{12}{5}

a = 2.4

So, the function for the Temperature is:

T(t) = 2.4t - 2

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Allison’s cupcake and cookie budget for her party is $105. She would like to have at least 40 cupcakes and cookies combined, and
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Answer:

a + b ≥ 40

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Step-by-step explanation:

We are told she would like to have at least 40 cupcakes and cookies combined.

If a is number of cupcakes and b is number of cookies, then this inequality is;

a + b ≥ 40

Secondly, we are told she would like to have at most 5 more cupcakes than cookies.

Thus, the inequality is;

a + 5 ≤ b

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4 0
3 years ago
1) Se o 5o e o 9-o termos de uma PA são, respectivamente, 40 e 68, então a razão r da progressão é: a) r = 6 b) r = 7 c) r = 9 d
Maslowich

Answer:

1) b) r = 7

2) e) 82

Step-by-step explanation:

Progressão aritmética:

Em uma progressão aritmética, a diferença entre termos consecutivos é sempre a mesma, chamada de razão.

O n-ésimo termo de uma PA é dado por, tomando o primeiro termo como referência:

a_n = a_1 + (n-1)r

Tomando o m-ésimo termo como referência, tem-se que:

a_n = a_m + (n-m)r

1) Se o 5o e o 9-o termos de uma PA são, respectivamente, 40 e 68, então a razão r da progressão é:

a_5 = 40, a_9 = 68. Então:

a_n = a_m + (n-m)r

68 = 40 + 4r

4r = 28

r = \frac{28}{4} = 7

Então a resposta correta é dada pela alternativa b.

2) Inserindo-se 6 números entre 72 e 107, de modo que a sequência (72, a2, a3, a4, a5, a6, a7 ,107) seja uma progressão aritmética, tem-se a3 igual a:

O primeiro termo é a_1 = 72 e o oitavo termo é a_8 = 107. Com isso, é possível encontrar a razão.

a_n = a_1 + (n-1)r

107 = 72 + 7r

7r = 35

r = \frac{35}{7} = 5

Então, o terceiro termo é:

a_3 = a_1 + 2r = 72 + 2(5) = 82

Logo, a resposta correta é dada pela alternativa e.

5 0
3 years ago
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