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irinina [24]
3 years ago
6

Find the angle measure of one internal angle for regular hexagon ABCDEF.

Mathematics
1 answer:
babunello [35]3 years ago
5 0

Answer:

Each interior angle of a polygon equals:

180 degrees - (360 / number of sides)

180 - (360 / 6)

= 180 -60

= 120 degrees

http://www.1728.org/polygon.htm

Step-by-step explanation:

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riding find the length of the hypotenuse of the right triangle use pencil and paper explain how you can interpret the Pythagorea
noname [10]

Solution

Question 1:

- Use of the area of squares to explain the Pythagoras theorem is given below

- The 3 squares given above have dimensions: a, b, and c.

- The areas of the squares are given by:

\begin{gathered} \text{For square of length }a\to a^2 \\ \text{For square of length }b\to b^2 \\ \text{For square of length }c\to c^2 \end{gathered}

- The Pythagoras theorem states that:

"The sum of the areas of the smaller squares add up to the area of the biggest square"

Thus, we have:

c^2=a^2+b^2

Question 2:

- We can apply the theorem as follows:

\begin{gathered} 10^2+24^2=c^2 \\ 100+576=c^2 \\ 676=c^2 \\ \text{Take square root of both sides} \\  \\ c=\sqrt[]{676} \\ c=26 \end{gathered}

Thus, the value of c is 26

7 0
1 year ago
Right triangle ABC has three sides with lengths AB= 119, BC = 169, CA= 120. Find the value of cos C. hint: draw and label the tr
GenaCL600 [577]

Answer:

\cos(C)=\frac{120}{169}

Step-by-step explanation:

The triangle is shown in the attachment.

Recall that;

\cos(C)=\frac{Adjacent}{Hypotenuse}

This implies that;

\cos(C)=\frac{|AC|}{|BC|}

We substitute the values into the ratio to obtain

\cos(C)=\frac{120}{169}


8 0
3 years ago
L33. Solve 41x - 7 + 12 = 28<br> Solution(s).
s2008m [1.1K]

Answer:

41x-7+12=28

41x+5=28

41x=28-5

41x= 23

x= 23/41

x= 0.56

7 0
3 years ago
OMG SUPER HARD QUESTION I DONT KNOW
zubka84 [21]

Answer:

1 apple

Step-by-step explanation:

unless you are a psycho who counts the one he ate as still in his possession,

therefore 2 - 1 = 1

hope this helps:)

6 0
2 years ago
Hello can you please help me posted picture of question
bogdanovich [222]

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C
6 0
3 years ago
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