Answer:
4 parrots
3 cages
Step-by-step explanation:
Bryan has one more parrot than cages and one more cage than half the number of parrots. The following system of equations can be modeled for the number of parrots (P) and cages (C):
Solving the linear system:
Bryan has 4 parrots and 3 cages.
The correct option is the last one. h is negative and k is positive.
<h3>
What can we say about h and k?</h3>
For the absolute value function:
g(x) = |x - h| + k
We know that the vertex is on the point (h, k).
On the graph, we can see that the vertex is on the point (-2, 1), then we have:
h = -2
k = 1
So the sign of h is negative and the sign of k is positive. The correct option is the last one.
If you want to learn more about absolute value functions:
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Answer:
C -16x + 74/5
Step-by-step explanation:
2(x + 7) - 18x + (4/5)
Expand the brackets.
2x + 14 - 18x + (4/5)
Combine like terms.
(2x - 18x) + (14 + (4/5))
-16x + 14 4/5
Convert 14 4/5 to an improper fraction
14 4/5 = ((14 * 5) + 4) / 5 = 74 / 5
Answer = -16x + 74/5
La probabilidad que se pueden calcular es:
c: Probabilidad de que el chocolate no tenga relleno de piña.
<h3>
¿Como encontrar las probabilidades?</h3>
Sabemos que hay 25 chocolates en total en la caja, tal que:
- 8 son de mora.
- 5 son de piña
- los 12 restantes son de fresa o cereza.
La probabilidad de obtener un tipo particular de sabor se obtiene como el cociente entre el número de chocolates de ese sabor y el total de chocolates.
La probabilidad que se pueden calcular es:
c: Probabilidad de que el chocolate no tenga relleno de piña.
Sabemos que 5 chocolates tienen relleno de piña, entonces 20 no tienen relleno de piña. es decir, la probabilidad es:
P = 20/25 = 4/5
Sí quieres aprender más sobre probabilidad:
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Differential<span> wheeled robot is a mobile robot whose movement is based on two separately driven wheels placed on either side of the robot body. It can thus change its direction by varying the relative rate of rotation of its wheels and hence does not require an additional </span>steering<span> motion.</span>
