Well, plug in all the values.
(sqrt)3>3
False. 3 would be more than it's square root.
(sqrt)9>3
3>3
This is false. 3 is not bigger than 3. They are equal.
(sqrt)15>3
3.8729..... >3
That is true,
(sqrt)10>3
3.1622>3
This true.
-3 and 0 would not work either.
So,
"C" and "D" are correct solutions.
I hope this helps!
~kaikers
Answer:
If two variables, X and Y, are negatively associated, in a linear way, then the above-average values of X will always be associated with below-average values of Y and vice-versa.
But not all points will fit the trend so the answer is NO, the above average values of X will not always be associated with below average values of Y.
Step-by-step explanation:
If two variables, X and Y, are negatively associated, in a linear way, then the above-average values of X will always be associated with below-average values of Y and vice-versa.
But not all points will fit the trend so the answer is NO, the above average values of X will not always be associated with below average values of Y.
Answer:The volume of the reservoirs in in^3 is:
V = 30*14*(3/2)*12* (since 1 ft = 12 in)
1 gal = 231 in^3
((7/8)V) : 231 = ((7/8)30*14*(3/2)*12)/231 = 28.64 gal
28.64 gallons of oil are required to fill the reservoir to 7/8 of its depth.
Step-by-step explanation: i hope this help you if not please let me know :)
Answer:
sin²x = (1 - cos2x)/2 ⇒ proved down
Step-by-step explanation:
∵ sin²x = (sinx)(sinx) ⇒ add and subtract (cosx)(cosx)
(sinx)(sinx) + (cosx)(cosx) - (cosx)(cosx)
∵ (cosx)(cosx) - (sinx)(sinx) = cos(x + x) = cos2x
∴ - cos2x + cos²x = -cos2x + (1 - sin²x)
∴ 1 - cos2x - sin²x = (1 - cos2x)/2 ⇒ equality of the two sides
∴ (1 - cos2x) - 1/2(1 - cos2x) = sin²x
∴ 1/2(1 - cos2x) = sin²x
∴ sin²x = (1 - cos2x)/2
