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Natasha2012 [34]

2 years ago

14

Armando tiene 25 chocolates en una caja y caja y cada chocolate tiene un relleno de 4 posibles fresa, mora y piña. De los 25 cho

colates de la caja de armando sabes que tiene 8 tienen relleno de mora y 5 de piña si una persona torna al azar un chocolate de la caja
cuales de la posibles posibilidades se puede calcular

1 answer:

Debora [2.8K]2 years ago

3 0

La probabilidad que se pueden calcular es:

c: Probabilidad de que el chocolate no tenga relleno de piña.

<h3>¿Como encontrar las probabilidades?</h3>

Sabemos que hay 25 chocolates en total en la caja, tal que:

8 son de mora.
5 son de piña
los 12 restantes son de fresa o cereza.

La probabilidad de obtener un tipo particular de sabor se obtiene como el cociente entre el número de chocolates de ese sabor y el total de chocolates.

La probabilidad que se pueden calcular es:

c: Probabilidad de que el chocolate no tenga relleno de piña.

Sabemos que 5 chocolates tienen relleno de piña, entonces 20 no tienen relleno de piña. es decir, la probabilidad es:

P = 20/25 = 4/5

Sí quieres aprender más sobre probabilidad:

brainly.com/question/24756209

#SPJ1

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What is 11d - 88. In algebraic expressions

bekas [8.4K]

Simplifying
11d + -88 = 0

Reorder the terms:
-88 + 11d = 0

Solving
-88 + 11d = 0

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '88' to each side of the equation.
-88 + 88 + 11d = 0 + 88

Combine like terms: -88 + 88 = 0
0 + 11d = 0 + 88
11d = 0 + 88

Combine like terms: 0 + 88 = 88
11d = 88

Divide each side by '11'.
d = 8

Simplifying
d = 8

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3 years ago

Function g is a transformation of the parent quadratic function f, which statements are true about this function g (x) = -(x-2)²

levacccp [35]

Answer:

Hello here is the answer Function g reflected function f across the x-axis.

For function g, as x approaches negative infinity, g(x) approaches negative infinity.

Function f is symmetrical about the point (4,6).

Step-by-step explanation:

let me know if u need help or adjustments

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3 years ago

4. You want to know if there's an association between college students' spring break destinations and what year they're in. You

Pachacha [2.7K]

Answer:

$\chi^2 =27.356$

$p_v = P(\chi^2_{9} >27.356)=0.00122$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(27.356,9,TRUE)"

Since the p value is lower than the significance level assumed 0.05 we can reject the null hypothesis at 5% of significance, and we can conclude that we have association between the two variables analyzed.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

Amusement Parks Mexico Home Other Total

Freshman 23 21 43 21 108

Sophomore 34 23 14 26 97

Junior 25 30 23 26 104

Senior 27 33 17 19 96

Total 109 107 97 92 405

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is independence between the two random variables

H1: There is dependence between the two variables

The level os significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{total col * total row}{grand total}$

And the calculations are given by:

$E_{1} =\frac{109*108}{405}=29.07$

$E_{2} =\frac{107*108}{405}=28.53$

$E_{3} =\frac{97*108}{405}=25.87$

$E_{4} =\frac{92*108}{405}=24.53$

$E_{5} =\frac{109*97}{405}=26.11$

$E_{6} =\frac{107*97}{405}=25.63$

$E_{7} =\frac{97*97}{405}=23.23$

$E_{8} =\frac{92*97}{405}=22.03$

$E_{9} =\frac{109*104}{405}=27.99$

$E_{10} =\frac{107*104}{405}=27.48$

$E_{11} =\frac{97*104}{405}=24.91$

$E_{12} =\frac{92*104}{405}=23.62$

$E_{13} =\frac{109*96}{405}=25.84$

$E_{14} =\frac{107*96}{405}=25.36$

$E_{15} =\frac{97*96}{405}=22.99$

$E_{16} =\frac{92*96}{405}=21.81$

And the expected values are given by:

Amusement Parks Mexico Home Other Total

Freshman 29.07 28.53 25.87 24.53 108

Sophomore 26.11 25.63 23.23 22.03 97

Junior 27.99 27.48 24.91 23.62 104

Senior 25.84 25.36 22.99 21.81 96

Total 109 107 97 92 405

And now we can calculate the statistic:

$\chi^2 =27.356$

Now we can calculate the degrees of freedom for the statistic given by:

$df=(rows-1)(cols-1)=(4-1)(4-1)=9$

And we can calculate the p value given by:

$p_v = P(\chi^2_{9} >27.356)=0.00122$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(27.356,9,TRUE)"

Since the p value is lower than the significance level assumed 0.05 we can reject the null hypothesis at 5% of significance, and we can conclude that we have association between the two variables analyzed.

7 0

3 years ago

What is the ratio of the volume of cylinder A to the volume of cylinder B.

ella [17]

Answer:

A:B

Step-by-step explanation:

i need numbers or something.

7 0

3 years ago

Help!!!! please!! i’m confused of this.

Juli2301 [7.4K]

Answer:

f(-3) = 44

Step-by-step explanation:

f(x) = 2x² - 5x + 11

Substitute the value.

f(-3) = 2(-3)² - 5(-3) + 11

Raise -3 to the power of 2.

f(-3) = 2(9) - 5(-3) + 11

Multiply 2 and 9.

f(-3) = 18 - 5(-3) + 11

Multiply -5 and -3.

f(-3) = 18 + 15 + 11

Add 18 and 15.

f(-3) = 33 + 11

Add 33 and 11.

f(-3) = 44

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3 years ago