Hypotenuse of a right triangles whose legs are square root of 10 and sqare root of 15
2 answers:
You might be interested in
Because 2 squares equal a meter u have to do four up down one. (Front elevation)
Then just four by one square on second row down(side elevation)
Then just four by one square on second row down(side elevation)
Consider the attached figure. If AB has length 1, then BC has length sin(15°) and CD (the altitude of triangle ABC) has length sin(15°)·cos(15°).
By the double angle formula for sin(α), ...
... sin(2α) = 2sin(α)cos(α)
Rearranging, this gives
... sin(α)·cos(α) = sin(2α)/2
We have
... CD = sin(15°)·cos(15°) = sin(2·15°)/2
... CD = sin(30°)/2 = (1/2)/2 = 1/4
That is, the altitude, CD, is 1/4 the hypotenuse, AB, of triangle ABC.
