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jasenka [17]
3 years ago
6

Hypotenuse of a right triangles whose legs are square root of 10 and sqare root of 15

Mathematics
2 answers:
almond37 [142]3 years ago
6 0
Sqrt{10}² + sqrt15² = c²

The square of any square root is that number without the square root sign

So now we have 10 + 15= c²
                            25     = c²
                     So c= 5
wlad13 [49]3 years ago
3 0

<span>10^2 + 15^2 = c^2 </span>

<span>100 + 225 = c^2 </span>

<span>325 = c^2 </span>

<span>Find the square root of both sides .... </span>

<span>18.02 = c = hypotenuse. </span>
You might be interested in
Question 8<br> Calculate the difference (4x2 + x - 5) – (5x2 - 1).
Rufina [12.5K]

Answer:

x - 6

Step-by-step explanation:

(4x2 + x - 5) - (5x2 - 1)

According to the order of operations, parenthesis come first so we will solve what is in the parenthesis first.

Then we do the multiplication because it comes before addition and subtraction.

4x2 = 8

Now we have 8 + x - 5

Combine like terms and 8-5=3 so we have 3 + x

Now for the second one.

5x2=10

10-1=9

Subtracting this from the first expression we have:

3+x-9 =

x - 6

7 0
2 years ago
I forgot how to do this can someone help me
Julli [10]
Planet A, because 7 x 10 > 5 x 10, the 28 is also bigger than 26. The numbers means 10 x 10 x 10 x 10... and so on to 28 or 26 (whatever the number is)
5 0
3 years ago
???????? ???????? ????????
atroni [7]
The answer would be A :))) hope you have a great day!
7 0
2 years ago
Help me I need please<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%20%7Bx%7D%5E%7B2%7D%20-%204%20%7D%20%5Ctimes%20%20%5Csq
Sauron [17]

Step-by-step explanation:

SEE THE IMAGE FOR SOLUTION ..

3 0
2 years ago
Read 2 more answers
How to do that? Thanks
Vladimir [108]
9) We need to find the limit as x approaches 2 of f(x) - g(x).
When we are approaching a certain value, we are essentially finding values that are infinitesimally approaching x = 2, to the point where we find the exact value when x hits 2.

Thus, by substituting x = 2 into f(x) - g(x), we are finding the value at which the functions' difference hits x = 2.

\lim_{x \to 2} [f(x) - g(x)] = \lim_{x \to 2}[\frac{3x + 2}{4} - x^{2} + 3]
= \frac{3(2) + 2}{4} - 2(2)^{2} + 3
= \frac{8}{4} - 8 + 3
= 2 - 8 + 3
= -3

Every other question repeats this process, so by applying the above process, your answers should come out smoothly.
Let me know if you need any more assistance, and I can guide you through them.
5 0
3 years ago
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