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svp [43]
4 years ago
10

A rectangle has length of 5.25 cm and area of 44.625 cm2. What does the length of the rectangle have to be?

Mathematics
1 answer:
vitfil [10]4 years ago
7 0

<u>Answer:</u>

The length of the rectangle is 8.5 cm

<u>Solution:</u>

The area of the rectangle is given as 44.625 cm^2

But we do not know the length of the rectangle, we are only given the width which is 5.25 cm.

We have been asked to find the length of the rectangle from the area and width.

So, let length and width be denoted as l and b respectively.

We know the area of the rectangle is  

\text { Area of rectangle }=l \times b=44.625 \mathrm{cm}^{2}

Now, we can substitute the values of width and area in eq1 and calculate the value of length

\begin{array}{l}{44.625=5.25 \times l} \\\\ {l=\frac{44.625}{5.25}=8.5}\end{array}

Therefore, by calculating we found out that the length of the rectangle is 8.5 cm.

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Answer:

\large\boxed{1.\ (4)^{-3x^2}=\left(\dfrac{1}{4}\right)^{3x^2}}

\large\boxed{2.\ ab^{-3x}=a\left(\dfrac{1}{b}\right)^{3x}=a\left[\left(\dfrac{1}{b}\right)^3\right]^x}

Step-by-step explanation:

Use:\ a^{-n}=\left(\dfrac{1}{a}\right)^n\\------------\\\\(4)^{-3x^2}=\left[(4)^{-1}\right]^{3x^2}=\left(\dfrac{1}{4}\right)^{3x^2}

Use:\ a^{-n}=\left(\dfrac{1}{a}\right)^n\ and\ (a^n)^m=a^{nm}\\--------------------\\\\ab^{-3x}=a\cdot b^{-3x}=a\left[(b)^{-1}\right]^{3x}=a\left(\dfrac{1}{b}\right)^{3x}\\\\ab^{-3x}=a\left(\dfrac{1}{b}\right)^{3x}=a\left[\left(\dfrac{1}{b}\right)^3\right]^x

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anastassius [24]

Answer:

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Step-by-step explanation:

1) In this question we've been given "a", the leading coefficient. and two roots:

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2) There's a theorem, called the Irrational Theorem Root that states:

If one root is in this form x'=\sqrt{a}+b  then its conjugate x''=\sqrt{a}-b. is also a root of this polynomial.

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x_3=-\sqrt{5}

3) So, applying this Theorem we can rewrite the equation, by factoring. Remembering that x is the root. Since the question wants it in this expanded form then:

f(x)=3(x-\sqrt{5})(x+\sqrt{5})(x-2)\Rightarrow 3x^{3}-6x^{2}-15x+30

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