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Juli2301 [7.4K]
4 years ago
6

Help Please

Physics
2 answers:
valentinak56 [21]4 years ago
8 0
Player #2 has the most momentum. Think it as if you are rolling a baseball, bowling ball, and softball down a hill. it will take more effort to stop the bowling  ball, because it has more momentum.

Talja [164]4 years ago
8 0

Answer:

Player-2 has the most momentum.

Explanation:

Momentum is defined as quantity of an motion in an object. It is calculated by multiplying mass of an object with its velocity.

Momentum(P) = Mass(m) × Velocity(v)

Players are running down the field at the same speed but in different directions.

Mass of player 1 =m_1=180 lbs = 81.64 kg

Velocity of the player 1 running towards south goal=v_1=v

Momentum of player 1 = P_1=81.64 kg\times v

Mass of player 2 =m_2=200 lbs = 90.71 kg

Velocity of the player 2 running towards north goal=v_2=v

Momentum of player 2 = P_2=90.71 kg\times v

Mass of player 3 =m_2=190 lbs = 86.18 kg

Velocity of the player 3 running towards north goal=v_3=v

Momentum of player 3 = P_3=86.18 kg\times v

Mass of player 4 =m_2=165 lbs = 74.84 kg

Velocity of the player 4 running towards south goal=v_4=v

Momentum of player 4 = P_4=74.84 kg\times v

Since, the velocity of all the players are equal the momentum of the player will depend upon their respective mass. Higher the mass of the player more will be momentum of the player.

In given case. the mass of player is highest which means that player 2 will have the most of the momentum.

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The Moon is 3.8 108 m from Earth and has a mass of 7.34 1022 kg. 5.97 1024 kg is the mass of the Earth.

<h3>What kind of gravitational pull does the moon have on the planet?</h3>

On the surface of the Moon, the acceleration caused by gravity around   1.625 m/s2 which is 16.6% greater than on the surface of the Earth 0.166.

<h3>What does the Earth's center's gravitational pull feel like?</h3>

Gravity is zero if you are in the centre of the earth since everything around you is pulling "up" (up is the only direction).

<h3>Where is the Earth's and the moon's gravitational centre?</h3>

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6 0
1 year ago
suppose that during any period of 1/4 second there is one instant at which the crests or troughs of component waves are exactly
ivanzaharov [21]
The correct answer for the question that is being presented above is this one: "(a)4." Suppose that during any period of 1/4 second there is one instant at which the crests or troughs of component waves are exactly in phase and maximum <span>reinforcement occurs, in 1 second, there will be 4 beats.</span>
8 0
3 years ago
Read 2 more answers
Hello!
34kurt
Iodine-131 has a half life of 8 days, so half of it is gone every 8 days.
10 grams of iodine-131 is left for 24 days.
At 8 days: 10/2=5 grams left
At 16 days: 5/2=2.5 grams left
At 24 days: 2.5/2=1.25 grams left.
**
Your mistake is that you stopped at 16 days.
8 0
3 years ago
If the acceleration due to gravity at the surface of planet x is double the value of earth's, how does planet x's mass compare t
love history [14]
There is not enough information given to answer with. The force of gravity at the planet's surface depends on the planet's radius as well as its mass. The planet could have exactly the same mass as Earth has. But if it's radius is only 71% of Earth's radius, then gravity on its surface will be twice as strong as gravity on Earth.
3 0
4 years ago
A 1000-kg car is moving at 30 m/s around a horizontal unbanked curve whose diameter is 0.20 km. What is the magnitude of the fri
omeli [17]

Answer:

4500 N

Explanation:

When a body is moving in a circular motion it will feel an acceleration directed towards the center of the circle, this acceleration is:

a = v^2/r

where v is the velocity of the body and r is the radius of the circumference:

Therefore, a body with mass m, will feel a force f:

f = m v^2/r

Therefore we need another force to keep the body(car) from sliding, this will be given by friction, remember that friction force is given a the normal times a constant of friction mu, that is:

fs = μN = μmg

The car will not slide if     f = fs,   i.e.

fs = μmg =  m v^2/r

That is, the magnitude of the friction force must be (at least) equal to the force due to the centripetal acceleration

fs = (1000 kg)  * (30m/s)^2 / (200 m) = 4500 N

7 0
4 years ago
Read 2 more answers
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