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iren2701 [21]
2 years ago
8

Math problem I need help with

Mathematics
2 answers:
Kruka [31]2 years ago
7 0

Answer:

31° is the answer thank you

elena55 [62]2 years ago
3 0
31 degrees Hopefully that helps!
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Can someone please help me with this? It would be greatly appreciated:) thanks
kati45 [8]

Answer:

d < 1

Step-by-step explanation:

First, we have to get d on the same side of the equation. So we will subtract d from both sides and the equation will be  12d-d < + 11. We could also write this problem as d(12-1) < 11, which when simplified would be d(11) < 11. Next, divide both sides by 11 and you get d< 1.   Hope this helps and have a great day!!:D

3 0
2 years ago
Leah claims that these figures are not similar. When she compared the heights, she wrote 27. Then she compared the bases and got
Flauer [41]

Answer:

<h2>Leah is actually wrong, because those rectangles are similar.</h2>

Step-by-step explanation:

Remember that similarity is about having proportional sides and congruent angles. When we have congruent sides, then those rectangles are congruent not similar.

In this case, to find the similarity, Leah should compare bases and heights thorugh division, because the ratio between heights and the ratio between bases must be equal. So, let's divide.

\frac{21}{6}=3.5

\frac{7}{2}=3.5

As you can observe, both ratios are equal.

Therefore, those rectangles are congruent.

4 0
3 years ago
I need help fast ....​
Cloud [144]
Since x=-10, plug that into the equation.

f(x) = 2(-10) + 11
= -20 + 11
y = -9

So the ordered pair in (x,y) terms is (-10,-9).
4 0
3 years ago
A car is on a driveway that is inclined 10 degrees to the horizontal. A force of 490 lb is required to keep the car from rolling
lara31 [8.8K]

Answer:

a) weight  of the car = 2816,1 lbs

b) 2773 lbs

Step-by-step explanation:

The equilibrium force is 490 lbs. That force keep the car at rest, then

∑ Fy  =  0     and  ∑Fx  =  0

Forces acting on the car:

The external force   490 lbs

weight of the car   uknown

Normal force

sin∠10°  =  0,174

cos∠10° = 0.985

∑Fx  =  0         mg*sin10°- 490 = 0      ∑Fy =  0      mg*cos10° - N  =  0

mg*0,174= 490

mg  =  490 / 0,174

mg = 2816,1 lbs

weight  of the car = 2816,1 lbs

The Normal force

mg*cos10° - N  =  0        2816,1 * 0,985 = N

N = 2773 lbs

Then equal force in magnitude and in opposite direction will car exets on the driveway

3 0
3 years ago
WORTH 30 POINTS PLZZZZZZZZZZZ HELP
Black_prince [1.1K]

Answer:

sqrt(5)*sqrt(5)=5.

Step-by-step explanation:


8 0
3 years ago
Read 2 more answers
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