Answer:
155
Step-by-step explanation:
The problem sounds complicated, but it's not. Let's analyse.
The city manager have come up with an equartion y=11x +12, with Y is the total number of the stores and X stands for how long it has been since 2003.
We can't explain how the manager came up with this equation, so iwe don't need to think of if the equation is real or not. Let's just base on what we have.
Because the equation aboce is a trendy line, it means that it would likely to be true with any X ( number of years since 1990).
In Tracy's case, the year is 2003, so it has been 2003 - 1990 = 13 years since 1990. This is the X in the equation. Now we only need to find Y in the equation, which is the number of retail stores there were in 2003, exactly what the problem asks.
y= 11x + 12
=> In Tracy's case: y= 11*13 + 12= 155
So the number of retail stores there were in 2003 was 155
Answer:
measure of what
Step-by-step explanation:
let me know
A = Anthony's weight
B = Anthony's brother's weight
A = 2B + 9 Plug in Anthony's weight
59 = 2B + 9 Subtract 9 from both sides
50 = 2B DIvide both sides by B
25 = B Switch the sides to make it easier to read
B = 25
Anthony's brother weighs 25 pounds.
I should be A hope this helps
<h2>
Answer with explanation:</h2>
It is given that:
f: R → R is a continuous function such that:
∀ x,y ∈ R
Now, let us assume f(1)=k
Also,
( Since,
f(0)=f(0+0)
i.e.
f(0)=f(0)+f(0)
By using property (1)
Also,
f(0)=2f(0)
i.e.
2f(0)-f(0)=0
i.e.
f(0)=0 )
Also,
i.e.
f(2)=f(1)+f(1) ( By using property (1) )
i.e.
f(2)=2f(1)
i.e.
f(2)=2k
f(m)=f(1+1+1+...+1)
i.e.
f(m)=f(1)+f(1)+f(1)+.......+f(1) (m times)
i.e.
f(m)=mf(1)
i.e.
f(m)=mk
Now,
Also,
i.e. 
Then,
(
Now, as we know that:
Q is dense in R.
so Э x∈ Q' such that Э a seq 
belonging to Q such that:
)
Now, we know that: Q'=R
This means that:
Э α ∈ R
such that Э sequence 
such that:
and
( since belongs to Q )
Let f is continuous at x=α
This means that:
This means that:
This means that:
f(x)=kx for every x∈ R
