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2 years ago

Simplify 7 sqrt3 - 4 sqrt 6 + sqrt 48 - sqrt 54. Directions please!

1 answer:

6 0

Simplify the expression.Exact Form:11√3−7√611⁢3-7⁢6Decimal Form:1.90613068

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Nine less than a number is no more than 8 and is no less than 3

frozen [14]

9 - x < 8 => -x < 8 - 9 => -x < -1 => x > 1

9 - x > 3 => -x > 3 -9 => -x > -6 => x < 6

So the number is between 1 and 6, notation 1 < x < 6

7 0

3 years ago

A boundary stripe 6 in. wide is painted around a rectangle whose dimensions are 120 ft by 230 ft. Use differentials to approxima

Nimfa-mama [501]

Answer:

350 square feet

Step-by-step explanation:

We are given that

Width of strip=6 in

Dimension of rectangle= $20 ft\times 230 ft$

We know that

Area of rectangle ,A=xy

Differentiate

$dA=\frac{\partial A}{\partial x}x+\frac{\partial A}{\partial y}y$

We have $\frac{\partial A}{\partial x}=y=230 ft$

$\frac{\partial A}{\partial y}=x=120$

$dx=\frac{12}{12}=1 ft$

1 ft=12 in

Because 6 in added in both side of breadth

dy= $\frac{12}{12}=1 ft$

Because 6 in added on both sides of length of rectangle

Substitute the values

$dA=230\times 1+120\times 1=350 ft^2$

Hence, the number of square feet of paint in the strip=350 square feet

7 0

3 years ago

Triangles are congruent if they have the same ______________.

slava [35]

Triangles are congruent if they have the same (Shape and Size).

5 0

3 years ago

Read 2 more answers

A box of donuts containing 6 maple bars, 3 chocolate donuts, and 3 custard filled donuts is sitting on a counter in a work offic

Svetlanka [38]

Probabilities are used to determine the chances of selecting a kind of donut from the box.

The probability that Warren eats a chocolate donut, and then a custard filled donut is 0.068

The given parameters are:

$\mathbf{Bars = 6}$

$\mathbf{Chocolate = 3}$

$\mathbf{Custard= 3}$

The total number of donuts in the box is:

$\mathbf{Total= 6 + 3 + 3}$

$\mathbf{Total= 12}$

The probability of eating a chocolate donut, and then a custard filled donut is calculated using:

$\mathbf{Pr = \frac{Chocolate}{Total}\times \frac{Custard}{Total-1}}$

So, we have:

$\mathbf{Pr = \frac{3}{12}\times \frac{3}{12-1}}$

Simplify

$\mathbf{Pr = \frac{3}{12}\times \frac{3}{11}}$

Multiply

$\mathbf{Pr = \frac{9}{132}}$

Divide

$\mathbf{Pr = 0.068}$

Hence, the probability that Warren eats a chocolate donut, and then a custard filled donut is approximately 0.068