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erma4kov [3.2K]
3 years ago
8

Choose SSS, SAS, or neither to compare

Mathematics
2 answers:
yulyashka [42]3 years ago
8 0

Answer:

SSS

Step-by-step explanation:

All sides are equal by SSS......

RSB [31]3 years ago
6 0

Answer:

SSS because one side is shared between the two triangles, so you know all three sides are equal.

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Hrozmarly needs to evaluate the following expression y^2-x^2 when y=9 and x=2. Her answer should be?
DENIUS [597]

Answer:

Step-by-step explanation:

y^2 -x^2=

y^2=9^2=81

x^2=2^2=4

81-4=77

3 0
3 years ago
Choose the numbers that are irrational.<br><br><br><br><br> 3.624<br> 0.6<br><br> 0.87<br> -5
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Answer:

-5 because the number is before zero which irrational number

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3 years ago
The bad debt ratio for a financial institution is defined to the dollar value of loans defaulted divided by the total dollar val
vlabodo [156]

Answer:

Step-by-step explanation:

From the information given:

Consider X to be the random variable denoting the bad debt ratios for Ohio Bank.

Then, X \sim N ( \mu, \sigma ^2)

Thus the null hypothesis and the alternative can be computed as:

Null hypothesis:

H_o :  \mu \leq3.5\%

Alternative hypothesis

H_1 : \mu > 3.5\%

The type I and type II error is as follows:

Type I:

The mean bad debt ratio is > 3.5% when it is not

Type II:

The mean bad debt ratio is ≤ 3.5% when it is not.

The test statistics can be calculated by using the formula:

t = \dfrac{\overline x - \mu}{\dfrac{\sigma}{\sqrt{n}}}

where;

sample size n = 7

mean = 6+8+5+9+7+5+8 = 48

sample mean \overline x =\dfrac{48}{7}

\overline x = 6.86

sample standard deviation is :

s = \sqrt{\dfrac{\sum( x -\overline x)^2}{n-1}}

s = \sqrt{\dfrac{( 6 -6.86)^2+( 8-6.86)^2+  ( 5 -6.86)^2 + ...+( 7 -6.86)^2+ ( 5 -6.86)^2+( 8 -6.86)^2 }{7-1}}

s = 1.573

population  mean \mu = 3.5

Therefore, the test statistics is :

t = \dfrac{\overline x - \mu}{\dfrac{\sigma}{\sqrt{n}}}

t = \dfrac{6.86- 3.5}{\dfrac{1.573}{\sqrt{7}}}

t = \dfrac{3.36}{\dfrac{1.573}{2.65}}

t = \dfrac{3.36\times {2.65}}{{1.573}}

t = 5.660

At significance level of 0.01

t_{0.01} = 3.707  

P - value = P(T > 5.66)

P - value = 1 - (T < 5.66)

P - value = 1 - 0.9993

P-value = 0.0007

Therefore, since t_{0.01} < t , we reject the null hypothesis and conclude that the claim that the mean bad debt ratio for Ohio banks is higher than the mean for all financial institutions is true.

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Answer:

the answer is 1/2

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