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stepladder [879]
3 years ago
13

How many solutions does this system

Mathematics
2 answers:
qaws [65]3 years ago
7 0

Answer:

B. One

Step-by-step explanation:

pochemuha3 years ago
7 0
X+2y=10
2x+8y=16

x=-2y+10

2x+8y=16
2(-2y+10)+8y=16
-4y+20+8y=16
4y=-4
y=-1

x=-2y+10
x=-2(-1)+10
x=2+10
x=12

This means that there can be only one solution (12,-1).
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It is A and if you dont think i an right all you have to do is add and see what number is the closest

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What is the ratio of x=8y
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Its going to be 8  y= x/8
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Help show work pleaeee
Inga [223]

SA = 2\pi rh+2\pir^2

1. Find the radius.

R = 1/2D

6 x 1/2 = 3

R = 3

2. Plug them in.

SA 2(3.14)(3)(7) + 2(3.14)(3^2)

3. Solve

3 x 7 = 21

21 x 3.14 = 65.94

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Its add math. i really need help, solve the question. thanks♥️​
dexar [7]

Answer:

see explanation

Step-by-step explanation:

Given

f(x) = ax + b

x = 2 → f(x) = 1 and x = - 1 → f(x) = - 5 ( from the table )

Substitute these values into f(x) = ax + b, that is

2a + b = 1 → (1)

- a + b = - 5 → (2)

Subtract (2) from (1) term by term to eliminate b

3a = 6 ( divide both sides by 3 )

a = 2

Substitute a = 2 into (2) and evaluate for b

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(b)

When x maps onto itself then

ax + b = x, that is

2x - 3 = x ( subtract x from both sides )

x - 3 = 0 ( add 3 to both sides )

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6 0
3 years ago
If f(x)=sinx 2x 1 and g is the inverse function of f
Bingel [31]

The value of the derivative of the function g(x) at x = 1 will be 1/3. Then the correct option is A.

<h3>What is an inverse function?</h3>

A function that may convert into another function is known as an inverse function or anti-function.

If the function is f(x) = sinx + 2x + 1.

Then the derivative of an inverse function g(x) of a function f(x) at a given value (a) will be

\rm g'(a) = \dfrac{1}{f'(g(a))}

The derivative of f(x) will be

f'(x) = cos x + 2

Then the given value of a will be

a = 1

g(x) = f⁻¹(x)

put x = 0, then we have

f(0) = sin 0 + 2(0) + 1

f(0) = 1

Put x = 1, in the function f⁻¹(x). Then we have

f⁻¹(1) = 0

and

g(1) = 0

Then put a = 1, then we have

\rm g'(a) = \dfrac{1}{f'(g(a))}\\\\g'(1) = \dfrac{1}{f'(g(1))}\\\\g'(1) = \dfrac{1}{f'(0)}\\\\g'(1) = \dfrac{1}{\cos 0 + 2}\\\\g'(1) = \dfrac{1}{1+2}= \dfrac{1}{3}

More about the inverse function link is given below.

brainly.com/question/2541698

#SPJ4

8 0
2 years ago
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