Answer:
The magnitude of the boat's velocity is 5.66 m/s
Step-by-step explanation:
Given;
Radius of curvature of the circular path, r = 40 m
speed of the boat, v = 0.8 t m/s
The magnitude of the boat's velocity when it has traveled 20 m is ?
a = dv / dt,
v = 0.8 t (differentiate with respect to t)
dv / dt = 0.8 = a
thus, a = 0.8 m/s²
If the boat starts from rest, initial velocity, u = 0
Apply kinematic equation, to solve for the boat velocity at 20 m
v² = u² + 2as
v² = 0 + 2 x 0.8 x 20
v² = 0 + 32
v² = 32
v = √32
v = 5.66 m/s
Therefore, the magnitude of the boat's velocity when it has traveled 20 m is 5.66 m/s
Answer:
D 36
Step-by-step explanation:
<em>Write the information algebraically</em>
c = 3a
c + a = 48
c = children, a = adults
<em>In the second sentence (in bold), we can replace c with 3a</em>
c + a = 48 → 3a + a = 48
<em>Simplify</em>
3a + a = 48 → 4a = 48 → a = 12 (divide both sides by 4)
<em>We can then substitute or plug in a = 12 into the original equation:</em>
c + a = 48 → c + 12 = 48 → c = 36 (subtract 12 from both sides)
<h3>There are 36 children</h3>
The answer would be 114. I did 3 times 38 and thats what i got. I hope it helps:D This is from your friendly Tolkien fan.
Answer:
x = -2, y = 2
Step-by-step explanation:
-7x + 7y = 28
7y = 28 + 7x
y = 4 + x ----(1)
-8x+4y=24 -----(2)
sub (1) into (2)
-8x+4(4+x)=24
-8x+16+4x = 24
-8x+4x = 24-16
-4x = 8
x = -2
sub x = -2 into (1)
y=4+(-2) = 2
Answer:
Area of rectangle=9×17=153 SQ.ft
Area of semi-circle=π9'2/2
Area of traingle=(1/2)×7×9=31.5
