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spin [16.1K]
3 years ago
7

Enter an equation in the form of y = MX + b that represents the function described by the graph ​

Mathematics
1 answer:
Molodets [167]3 years ago
3 0

Answer:

y=2/3+3

Step-by-step explanation:

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Please solve. best answer gets rewarded! show step by step.
sukhopar [10]
Hey!

Let's write the problem.
2x-4-5x=2
Add like terms...
-3x-4=2
Add 4 to both sides.
-3x-4+4=2+4
-3x=6
Divide both sides by -3.
\frac{-3x}{-3}=\frac{6}{-3}

Our final answer would be,
x=-2

Thanks!
-TetraFish
4 0
3 years ago
Read 2 more answers
Is (2, 4) a solution to the system<br> y = 2x<br> x + y = 6
posledela

Answer:

yes you plug the numbers in

5 0
3 years ago
Two angles of a quadrilateral measure 325° and 10°. The other two angles are in a ratio of 2:3. What are the measures of those t
Dmitry_Shevchenko [17]

Answer:

The answer is 60 and 80

Step-by-step explanation:

7 0
2 years ago
Please Help!!!..............................
Karo-lina-s [1.5K]

Answer:

The first choice.

Step-by-step explanation:

Your graph should look like one below.

5 0
3 years ago
How do you determine if a relation is quadratic by calculation differences, analyzing a graph, examining the degree in an equati
Kryger [21]

1) We can determine by the table of values whether a function is a quadratic one by considering this example:

x | y 1st difference 2nd difference

0 0 3 -0 = 3 7-3 = 4

1 3 10 -3 = 7 11 -7 = 4

2 10 21 -10 =11 15 -11 = 4

3 21 36-21 = 15 19-5 = 4

4 36 55-36= 19

5 55

2) Let's subtract the values of y this way:

3 -0 = 3

10 -3 = 7

21 -10 = 11

36 -21 = 15

55 -36 = 19

Now let's subtract the differences we've just found:

7 -3 = 4

11-7 = 4

15-11 = 4

19-15 = 4

So, if the "second difference" is constant (same result) then it means we have a quadratic function just by analyzing the table.

3) Hence, we can determine if this is a quadratic relation calculating the second difference of the y-values if the second difference yields the same value. The graph must be a parabola and the highest coefficient must be 2

4 0
1 year ago
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