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trasher [3.6K]
2 years ago
11

9. You are installing a swimming pool. Write a polynomial that represents the area of the walkway

Mathematics
1 answer:
Anastasy [175]2 years ago
6 0

Answer:

  (10x² +12x +32) ft²

Step-by-step explanation:

The area of the walkway around the pool is the difference between the area of the entire rectangle, and the area of the pool. The area of each rectangle is found by multiplying its length and width.

__

<u>Overall area</u>:

  ((2x +6) ft) × (10x) ft = (10x² +60x) ft²

<u>Pool area</u>:

  ((6x -4) ft) × (8 ft) = (48x -32) ft²

<u>Walkway area</u>:

  overall area - pool area = ((10x² +60x) ft²) -((48x -32) ft²)

  = (10x² +12x +32) ft²

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3u - 10 =23<br> Simplify your answer as much as possible.<br> Ü<br> Х
borishaifa [10]

Answer:

u=11

Step-by-step explanation:

3u - 10 = 20

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4 0
2 years ago
Is there statistically significant evidence that the districts with smaller classes have higher average test​ scores? The t​-sta
Musya8 [376]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The  95% confidence interval is [670.03  , 673.97 ]

The  test statistics is t = 7.7

The  p-value  is    p-value  =  0

The <u>p-value</u>  suggests that the null hypothesis is<u> rejected </u>with a high degree of confidence. Hence  <u>there is</u> statistically significant evidence that the districts with smaller classes have higher average test score  

Step-by-step explanation:

From the question we are told that

   The sample size is  n =  408

    The sample mean is  \= y  =  672.0

   The standard deviation is  s = 20.3

Given that the confidence level  is 95% then the level of significance is  

   \alpha = (100 -95 )\% = 0.05

From the normal distribution table  the critical value of \frac{\alpha }{2} = \frac{0.05 }{2} is  

    Z_{\frac{\alpha }{2} } =  1.96

Generally  the margin of error is mathematically represented as  

     E  =  Z_{\frac{\alpha }{2} } *  \frac{s}{\sqrt{n} }

=>   E  =  1.96 *  \frac{20.3}{\sqrt{408} }

=>     E  =  1.970

Generally the 95% confidence interval is mathematically represented as

       \= y -E  < \mu <  \= y + E

=>     672.0 -1.970  < \mu < 672.0 +1.970

=>     670.03  < \mu < 673.97

=>     [670.03  , 673.97 ]

From the question we are told that

   Class size                                  small                                      large

  Avg.score(\= y)         \= y_1 = 683.7   \= y_2 =  676.0

   S_y                          S_{y_1} =20.2    S_{y_2} = 18.6

   sample size                             n_1 = 229        n_2 =  184

The  null hypothesis is  H_o :  \mu_1 - \mu_2 = 0

The alternative hypothesis is  H_a :  \mu_1 - \mu_2 > 0

Generally the standard error for the difference in mean is mathematically represented as

       SE =  \sqrt{\frac{S_{y_1}^2 }{n_1} +\frac{S_{y_2}^2 }{n_2}   }

=>     SE =  \sqrt{20.2^2 }{229} +\frac{18.6^2 }{184_2}   }

=>     SE =  1.913

Generally the test statistics is mathematically represented as

      t = \frac{\= y _1 - \= y_2 }{SE}

=>    t = \frac{683.7 - 676.0 }{1.913}

=>   t = 7.7

Generally the p-value is mathematically represented as

    p-value  =  P(t >  7.7 )

From the  z-table

        P(t >  7.7 ) =  0

So

   p-value  =  0

From the values we obtained and calculated we can see that p-value  <  \alpha

This mean that

The p-value  suggests that the null hypothesis is rejected with a high degree of confidence. Hence  there is statistically significant evidence that the districts with smaller classes have higher average test score  

4 0
3 years ago
Twice the sum of a number and six decreased by fifteen is the same as eighteen more than the product of five and the number. Fin
Arlecino [84]

Answer:

-9

Step-by-step explanation:

2(n+6) -15 = 5n+18

2n + 12 - 15 = 5n + 18

2n - 3 = 5n + 18

2n = 5n + 21

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n = -9

4 0
3 years ago
HELP ASAP
Sindrei [870]

Answer:

median = 27

range = 29

mode = 32

maximum value = 41

interquartile range = 21

minimum = 12

upper quartile = 35

mean = 25

lower quartile = 14

Step-by-step explanation:

hope i helped

8 0
3 years ago
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