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natulia [17]
3 years ago
14

Write the slope-intercept form of the equation for the line passing through the given pair of points. (-9, 0) and (6, 4)

Mathematics
1 answer:
ra1l [238]3 years ago
8 0
Hope you understand :)

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olga nikolaevna [1]
The square root of 147 when rounded to the nearest tenth is about 12.1
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Factor the polynomial x2 + 2x – 3x – 6 by double grouping. Group terms with common factors: (x2 + 2x) + (– 3x – 6) Factor the GC
garik1379 [7]

We have been given a polynomial and we are asked to factor our polynomial by double grouping.

x^{2} +2x-3x-6

First of all we will group terms with common factors. We can see that x^{2} and 2x have a common factor x. Common factor of -3x and -6 is -3.

x^{2} +2x-3x-6

(x^{2} +2x)+(-3x-6)

Now we will factor out Greatest Common Factor from each group.

x(x+2)-3(x+2)

After factoring out GCF from each group we got (x+2) as our common binomial.  Now we will write our polynomial as a product of two binomials as:

(x+2)(x-3)

Therefore, our polynomial as a product of two binomials will be (x+2)(x-3).  

8 0
3 years ago
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The box plots show the average gas mileage, in miles per gallon, of cars and minivans tested by a certain company.
mr_godi [17]

Answer:

b.The interquartile range for cars is about 7 mpg, and the interquartile range for minivans is about 3 mpg.

Step-by-step explanation:

i got it right

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Travis is deciding how to study math tonight he is choosing between studying ofG patterns P or equations E he also is deciding w
expeople1 [14]

Answer:

GT, GV, PT, PV, ET, and EV.

Step-by-step explanation:

Given that

The number of topics Travis has to chose from are 3 topics(G, P, E).

The number of ways Travis can study each topic are 2 ways(T, V).

Essentially, the number of combinations Travis is expected to be able to chose from is given as

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The number of combinations = 3 * 2

The number of combinations = 6

Therefore, the total possible combinations has to be

GT, GV, PT, PV, ET, and EV

7 0
3 years ago
Viola drives 2 kilometers up a hill that makes an angle of 9 with the horizontal. To the nearest tenth of a kilometer, what hori
Elenna [48]


cosine ( CAH) = Adjacent/ hypothenus

cos9 = x/ 2

let x represent the horizontal distance

2 cos 9  = x

x = 2 (0.98768834)

x = 1.975

x = 1.97

therefore the horizontal dstance jade covers is 1.97km

8 0
4 years ago
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