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bekas [8.4K]
3 years ago
14

Find the value of x in the shown figure

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
3 0
Im not really sure if im right but i think the answer is 140-

Explanation:
I added 30+10 which equalled 40 and then i noticed the circle which would equal 360 and subtracted it from the 40 however that got me more then i needed since it wasnt one of the choices. Then i thought hmm maybe its a supplementary angle which usually equals 180 so i subtracted it from 40 which got me 140! Like i said i dont know if im right or not :(
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#0000 geometery help please am i correct
Aneli [31]
Yes you are right . In any triangle the 3 medians intersect in one point called centroid

4 0
2 years ago
Here's the question. ​
OleMash [197]

Answer:

The value of T₂₀ - T₁₅ is <u>-20</u>.

Step-by-step explanation:

<u>Given</u> :

  • >> If for an A.P, d = -4

<u>To</u><u> </u><u>Find</u> :

  • >> T₂₀ - T₁₅

<u>Using Formula</u> :

General term of an A.P.

\star{\small{\underline{\boxed{\sf{\red{ T_n = a  + (n - 1)d}}}}}}

  • >> Tₙ = nᵗʰ term
  • >> a = first term
  • >> n = no. of terms
  • >> d = common difference

<u>Solution</u> :

Firstly finding the A.P of T₂₀ by substituting the values in the formula :

{\dashrightarrow{\pmb{\sf{ T_n = a  + (n - 1)d}}}}

{\dashrightarrow{\sf{ T_{20} = a  + (20 - 1) d}}}

{\dashrightarrow{\sf{ T_{20} = a  + (19)d}}}

{\dashrightarrow{\sf{ T_{20} = a  + 19  \times d}}}

{\dashrightarrow{\sf{ T_{20} = a  + 19d}}}

{\star \: {\underline{\boxed{\sf{\pink{ T_{20} = a  + 19d}}}}}}

Hence, the value of T₂₀ is a + 19d.

\rule{190}1

Secondly, finding the A.P of T₁₅ by substituting the values in the formula :

{\dashrightarrow{\pmb{\sf{ T_n = a  + (n - 1)d}}}}

{\dashrightarrow{\sf{ T_{15}= a  + (15 - 1) d}}}

{\dashrightarrow{\sf{ T_{15}= a  + (14) d}}}

{\dashrightarrow{\sf{ T_{15}= a  + 14 \times d}}}

{\dashrightarrow{\sf{ T_{15}= a  + 14d}}}

{\star{\underline{\boxed{\sf \pink{ T_{15}= a  + 14d}}}}}

Hence, the value of T₁₅ is a + 14d

\rule{190}1

Now, finding the difference between T₂₀ - T₁₅ :

{\dashrightarrow{\pmb{\sf{T_{20} -  T_{15}}}}}

{\dashrightarrow{\sf{(a + 19d) -  (a + 14d)}}}

{\dashrightarrow{\sf{a + 19d -  a  -  14d}}}

{\dashrightarrow{\sf{a - a + 19d -  14d}}}

{\dashrightarrow{\sf{0+ 19d -  14d}}}

{\dashrightarrow{\sf{19d -  14d}}}

{\dashrightarrow{\sf{5 \times  - 4}}}

{\dashrightarrow{\sf{ - 20}}}

{\star \: \underline{\boxed{\sf{\pink{T_{20} -  T_{15} =  - 20}}}}}

Hence, the value of T₂₀ - T₁₅ is -20.

\underline{\rule{220pt}{3.5pt}}

3 0
2 years ago
What is the amplitude of the cosine function corresponding to the secant function graphed below ? a. -2 b. -1 c. 2 d. 3
Bas_tet [7]

Answer:

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Step-by-step explanation:

From the graph, we obtain the trigonometric function as:

y=2 \sec x+1

The corresponding cosine function have equation.

y=2\cos x+ 1

This function is of the form: y=a\cos bx+c

where |a| is the amplitude.

Therefore the amplitude is |2|=2

The third choice is correct

7 0
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Hunter-Best [27]

Answer:

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Step-by-step explanation:

that is my answer

5 0
3 years ago
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GREYUIT [131]

Answer:

6547

Step-by-step explanation:

6 0
3 years ago
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