Question

Hello, can you help me please​

Answer 1

Step-by-step explanation:

1. C(x) is in vertex form so let write the function out.

$a(x - 1) {}^{2} + b$

B is our maximum value so b=9.

$a(x - 1) { }^{2} + 9$

To find a, we know that when x=5 is a root so plug 5 in for x to find a.

$a(5 - 1) {}^{2} + 9 = 0$

$a(4) {}^{2} + 9 = 0$

$16a = - 9$

$a = - \frac{9}{16}$

2.. Let convert Chelesa function into. standard form.

$\frac{ -9 }{16} (x - 1) {}^{2} + 9$

$- \frac{9}{16} (x {}^{2} - 2x + 1) + 9$

$- \frac{9}{16} {x}^{2} + \frac{9}{8} x + \frac{135}{16}$

Let see which value has the higher constant.

135/16 is more than 8 so Chelsea jumper higher.

3. Set Herritea equation equal to zero.

$- \frac{2}{9} {x }^{2} + 8 = 0$

$- \frac{2}{9} x {}^{2} = - 8$

Multiply both sides by the reciprocal of negative 2/9.

${x}^{2} = - 8 \times - \frac{9}{2}$

${x}^{2} = 36$

$x = 6$

We talking positive distance so the answer is she has moved 6 units horinzontial.

4. The domain of C is all real numbers and the range is All real numbers that are less than or equal to 9.

The domain of H is all real numbers, the range of H is all real numbers that are less than or equal to 8.

5. That means that the y values are equal when x=3.7