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3 years ago

The image of (-9,-4) after a reflection over the y-axis?

Mathematics

1 answer:

lidiya [134]3 years ago

7 0

Answer:

The answer is (-4,9)

Step-by-step explanation:

When you reflect across y=-x the x and y coordinates switch places and change signs.

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The area of the surface of a pool table is 24 square feet. The perimeter is 22 feet. What are the dimensions of the pool table?

trasher [3.6K]

Answer: The dimensions are 8 and 3

Step-by-step explanation:

So 8*3=24 which corresponds with the formula for area l*w= Area

And perimeter means we add up all 4 sides so

8+8+3+3= 22

So the dimensions are 8 and 3

5 0

3 years ago

Please need help with one

elixir [45]

The answer is 88 cube units.

3 0

3 years ago

Can someone Answer this?

Misha Larkins [42]

Answer:

The limit of the function as x approaches 1 is ∞

Vertical asymptote; x = 1

Step-by-step explanation:

The graphical approach to evaluating limits involves graphing the function, the graph of the function $\frac{1}{(x-1)^{2} }$ is contained in the attachment below.

The red vertical line is the graph of x = 1. As we approach the line x = 1 from the left, the value of the function, that is y becomes large and large indefinitely. That is the value of the function approaches infinity. The same case applies when we approach the vertical line x = 1 from the right.

Also noticeable is the fact that the function approaches the line x = 1 asymptotically. The function gets closer and closer to this line but actually never touches it. Therefore, the line x = 1 is our vertical asymptote of the function given

7 0

3 years ago

Two statistics teachers both believe that each has the smarter class. To put this to the test, they give the same final exam to

SVETLANKA909090 [29]

Answer:

We conclude that there is no difference between the two classes.

Step-by-step explanation:

We are given that two statistics teachers both believe that each has a smarter class.

A summary of the class sizes, class means, and standard deviations is given below:n1 = 47, x-bar1 = 84.4, s1 = 18n2 = 50, x-bar2 = 82.9, s2 = 17

Let $\mu_1$ = mean age of student cars.

$\mu_2$ = mean age of faculty cars.

So, Null Hypothesis, $H_0$ : $\mu_1=\mu_2$ {means that there is no difference in the two classes}

Alternate Hypothesis, $H_A$ : $\mu_1\neq \mu_2$ {means that there is a difference in the two classes}

The test statistics that will be used here is Two-sample t-test statistics because we don't know about the population standard deviations;

T.S. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t_n_1_+_n_2_-_2$

where, $\bar X_1$ = sample mean age of student cars = 8 years

$\bar X_2$ = sample mean age of faculty cars = 5.3 years

$s_1$ = sample standard deviation of student cars = 3.6 years

$s_2$ = sample standard deviation of student cars = 3.7 years

$n_1$ = sample of student cars = 110

$n_2$ = sample of faculty cars = 75

Also, $s_p=\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(47-1)\times 18^{2}+(50-1)\times 17^{2} }{47+50-2} }$ = 17.491

So, the test statistics = $\frac{(84.4-82.9)-(0)}{17.491 \times \sqrt{\frac{1}{47}+\frac{1}{50} } }$ ~ $t_9_5$

= 0.422

The value of t-test statistics is 0.422.

Now, the P-value of the test statistics is given by;

P-value = P( $t_9_5$ > 0.422) = From the t table it is clear that the P-value will lie somewhere between 40% and 30%.

Since the P-value of our test statistics is way more than the level of significance of 0.04, so we have insufficient evidence to reject our null hypothesis as our test statistics will not fall in the rejection region.

Therefore, we conclude that there is no difference between the two classes.

6 0

3 years ago

I need help Raj plotted point L in the coordinate plane below.

Ivenika [448]

Answer:

1÷3=4/,*_,^5,%"2#'d3cfcfj3c2kdxm2e

Step-by-step explanation:

wdcfeb5hnj6nefcs

6 0

3 years ago

Read 2 more answers