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telo118 [61]
3 years ago
8

A family buys 6 airline tickets online. The family buys travel insurance that costs ​$18 per ticket. The total cost is ​$1,038.

Let x represent the price of one ticket. Write an equation for the total cost. Then find the price of one ticket.
the price of one ticket is ​$_________
Mathematics
1 answer:
scZoUnD [109]3 years ago
5 0
The price of the tickets is $155
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Sarah needs to make 20 same-size tablecloths using 35 yards of fabric. How many inches of fabric will she use per tablecloth?
Illusion [34]

Answer:

63 inches per tablecloth.

Step-by-step explanation:

35 / 20 = 1.75 yards per tablecloth,

= 1.75 * 36

= 63 inches.

6 0
3 years ago
What is the area of this triangle? and can you give me the equation on how to solve it? thank you!
andrew11 [14]
The area of the triangle is 4.75.
You times 1.9 (the height) and 5 (the base) then divide the product by 2.
A = 1.9km x 5km / 2
8 0
3 years ago
Jarrett's puppy weighed 3 3/4 ounces at Birth. At 1 week old, the puppy weighed 5 1/8 ounces. At 2 weeks old, the puppy weighed
Ad libitum [116K]

Answer:  The answer is 7\dfrac{7}{8} ounces.

Step-by-step explanation: Given in the question the weight of Jarrett's puppy at birth, one week old and 2 weeks old are as follows:

b_0=3\dfrac{3}{4}=\dfrac{15}{4}~\textup{ounces},\\\\\\b_1=5\dfrac{1}{8}=\dfrac{41}{8}~\textup{ounces},\\\\\\b_3=6\dfrac{1}{2}=\dfrac{13}{2}~\textup{ounces}.

We can see that

b_1-b_0=b_2-b_1=\dfrac{11}{8}.

So, the weight of the baby will make an arithmetic progression with first term 'a' and common difference 'd' as follows:

b_0=\dfrac{15}{4},~~d=\dfrac{11}{8}.

Thus, the weight of the puupy after 3 weeks will be

b_3=b_0+3\times d=\dfrac{15}{4}+3\times\dfrac{11}{8}=\dfrac{30+33}{8}=\dfrac{63}{8}=7\dfrac{7}{8}~\textup{ounces}.

5 0
4 years ago
Read 2 more answers
4. An observer at the top of a 40-foot cliff spots two boats sailing in a straight line with her. The
Tems11 [23]

Answer:

The two bolts of 50.9 ft apart

Step-by-step explanation:

boat 1

\tan(21)  =  \frac{45.33}{x}  \\ x =  \frac{45.33}{ \tan(21) }  \\ x = 118.1 \: ft

boat 2

\tan(34)  =  \frac{45.33}{x}  \\ x =  \frac{45.33}{ \tan(34) }  \\ x = 67.2 \: ft

118.1 - 67.2 = 50.9 \: ft

8 0
3 years ago
Two numbers have a sum of 21, and 3
Oksi-84 [34.3K]

Answer:

Step-by-step explanation: let the first number be x and the second number be y

according to the condition given

x+y=21

3x-y=43

using elimination method

3x+3y=63

3x-y=43

subtacting both the equations

4y=20

y=20/4

y=5

substituting value of y in eq 1

x+5=21

x=21-5

x=16

therefore x=16 and y=5

the two numbers are 16 and 5

4 0
4 years ago
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