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Svetllana [295]
3 years ago
9

The perimeter of a rectangle is 56 inches. The length is 4 more than twice the width. Write and solve a system to determine the

length of the rectangle
Mathematics
2 answers:
irina1246 [14]3 years ago
8 0

Answer:

56×4=x

so x=224

Step-by-step explanation:

if i am  wrong sorry didnt fully understand what you wanted

Marianna [84]3 years ago
5 0
Width: x
length: x + 4
Equation: 2(x + x + 4) = 56
2(2x + 4) = 56
4x + 8 = 56
4x = 48, x = 12
Width = 12, 12 + 4 = length
Solution: the length is 16 inch
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I hope this helped
8 0
3 years ago
Read 2 more answers
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Katena32 [7]

Answer:

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Step-by-step explanation:

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2 years ago
Help!!!! Number 4 right answer
USPshnik [31]
The answer would be 0 solutions.

Here, we see <em>|</em><em />x+6<em>|</em><em /> = 2.
Oh wow! A foreign object!
|x+6|... two lines... what is that?

That is called absolute value. Whatever is inside the two lines, must have a positive answer!

Let's pretend we have a machine that has this absolute value function activated.
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Let's put in -6.

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So, for how many values <em>x</em> is |x+6|=-2 true?

None, because the answer <em>must</em><em /> be positive! 
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3 years ago
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tia_tia [17]

Answer:

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4 years ago
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Rzqust [24]

Answer:

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3 years ago
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