Answer:
(a) 74553
(b) 172120
(c) 234802
Step-by-step explanation:
Given

Solving (a): 1998
Year 1998 means that:


So, we have:




--- approximated
Solving (b): 2003
Year 2003 means that:


So, we have:




--- approximated
Solving (c): 2006
Year 2006 means that:


So, we have:




--- approximated
Answer:
13 4/5 = 10 + 3 4/5
Step-by-step explanation:
Yes, since 50 x 10 = 500.
B. 54 meters
first you want to set up your ratios and cross multiply to figure out the number to square l's ratio. which would be 10.8.
then use formula for perimeter
2(l)+2(w)=9
2(10.8)+2(18)=53.6-rounded =54<span />