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Mars2501 [29]
3 years ago
7

Quiz question!! i need help fast !

Mathematics
1 answer:
mixas84 [53]3 years ago
7 0

Answer:

200-5x and 90

Step-by-step explanation:

we don't know how many weeks she spent at first so we make the equation 200-5x

and then it would be 5x22 which is 110

so 200-110=90

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A person makes 300 dollars a month babysitting. If they
Keith_Richards [23]

Answer:

They will save $90 each month

Step-by-step explanation:

300*30%

or

300*.3

90

7 0
3 years ago
If two are supplementary and one of the angles measure 62 what is the measure of the other angle
Juli2301 [7.4K]
Supplementary angles add to equal 180 degrees. If two angles are supplements of each other and one of the angles measures 62 degrees, you can set its sum with the unknown angle, x, equal to 180 and solve for the unknown angle x.

Equation:
180 = x + 62

Subtract 62 from both sides:
118 = x

Answer:
The measure of the other angle is 118°.
8 0
3 years ago
(02.01 MC) When a figure is translated on a coordinate grid, what conclusion can you draw from the pre-image and image?
Tanya [424]
Translation doesn't change the lengths of the sides or
the size of the angles. So when a figure is just translated,
the original image and the translated image are congruent. 
7 0
4 years ago
Help me with 4 and 5 please!!!!!<br> Due tomrrow
MArishka [77]
4 times 2 is 8 and 8-4 is 4 so 4 X10 is 40 plus 8 is 48
3 0
3 years ago
A simple random sample of 10 paired values (x,y) yields the following statistical calculations: ∑x=108, ∑y=138, ∑(x2) =1249, ∑(y
lora16 [44]

The linear correlation coefficient is r=1.054

Explanation:

It is given that $\Sigma x=108$,  $\Sigma y=138$ , $\Sigma x^{2} =1249$ , $\Sigma y^{2} =2280$ and $\Sigma(x y)=1676$

Also, the random sample is n=10

The formula to determine the correlation coefficient is given by

$r=\frac{n\left(\sum x y\right)-\left(\sum x\right)(\Sigma y)}{\sqrt{\left[n \sum x^{2}-\left(\sum x\right)^{2}\right]\left[n \Sigma y^{2}-(\Sigma y)^{2}\right]}}$

Substituting the values in the formula, we have,

$r=\frac{10(1676)-(108)(138)}{\sqrt{\left[10(1249)-(108)^{2}\right]\left[10(2280)-(138)^{2}\right]}}$

Simplifying the values, we get,

$r=\frac{16760-14904}{\sqrt{\left[12490-11664\right]\left[22800-19044\right]}}$

Subtracting the values in both numerator and denominator, we have,

$r=\frac{1856}{\sqrt{\left[826\right]\left[3756\right]}}$

Multiplying the denominator,

$r=\frac{1856}{\sqrt{3102456}}$

Simplifying, we have,

$r=\frac{1856}{1761.4}$

Dividing, we get,

r=1.054

Thus, the linear correlation coefficient is r=1.054

7 0
3 years ago
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