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Aleks [24]
3 years ago
5

What is the standard form of a quadratic with a root of

mula1" title="2i \sqrt{3} " alt="2i \sqrt{3} " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
kari74 [83]3 years ago
5 0

Step-by-step explanation:

2\sqrt{ - 3}

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Through: (3, 4), slope = -2​
sineoko [7]

Answer:

y = -2x - 2

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

Points: (3, 4)

Slope: -2

y = -2x + b

4 = -2 ( 3 ) + b

4 = -6 + b

b = -2

y = -2x - 2

8 0
3 years ago
Read 2 more answers
I thought it was the second one
lawyer [7]

the second one y=(2/3)x

4 0
3 years ago
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8x - 14 = 7.7x + 3x
djverab [1.8K]

Answer:

x=5.2

Step-by-step explanation:

8x−14=7.7x+3x

Step 1: Simplify both sides of the equation.

8x−14=7.7x+3x

8x+−14=7.7x+3x

8x−14=(7.7x+3x)(Combine Like Terms)

8x−14=10.7x

8x−14=10.7x

Step 2: Subtract 10.7x from both sides.

8x−14−10.7x=10.7x−10.7x

−2.7x−14=0

Step 3: Add 14 to both sides.

−2.7x−14+14=0+14

−2.7x=14

Step 4: Divide both sides by -2.7.

−2.7x /−2.7  = 14 /−2.7

x=−5.185185 or 5.2

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3 years ago
C=[?]cm<br> Find c round to the nearest tenth
frosja888 [35]

Answer:

56.3cm

Step-by-step explanation:

Check attachment

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A truck can be rented from Company A for $90 a day plus $0.20 per mile. Com
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