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Butoxors [25]
3 years ago
15

Which expression is equivalent to 10x+9+10x+1010x+9+10x+10?

Mathematics
2 answers:
Bumek [7]3 years ago
7 0

Answer:

ybcdafhuaydf

Step-by-step explanation:

i

dsf

ds

fds

f

dsf

Damm [24]3 years ago
5 0

: 10x + 10x +1010+ 10x= 1040x

9+9=18

Answer 1014x+ 18

Step-by-step explanation:

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Answer:

circumference of the circle=2πr

2 \times 3.142 \times 0.9 \\5.6556cm

5.7 cm

5 0
3 years ago
1) -7v + 4(2 - 5v) = -154
Bad White [126]

Answer:

v=6

Step-by-step explanation:

First let's simplify the equation so it will be easier to PEMDAS the equation later.

-7v+4(2-5v)=-154

-7v+8-20v=-154

-27v+8=-154

Now you must isolate the v variable. You do this by subtracting 8 first and then divide by -27.

-27v+8=-154

-27v=-162

v = 6

5 0
3 years ago
Bill rented a truck for one day.There was a base fee of $15.95,and there was a additional charge of 92 cents for each mile drive
ANTONII [103]

Answer:

27.85 remainder 7

Step-by-step explanation: devide something

5 0
4 years ago
The data set represents the number of rings each person in a room is wearing. 0, 2, 4, 0, 2, 3, 2, 8, 6 What is the interquartil
forsale [732]

Answer:

IQR=4

Step-by-step explanation:

We have been given a data set that represents the number of rings each person in a room is wearing as: 0, 2, 4, 0, 2, 3, 2, 8, 6. We are asked to find the interquartile range of the data.

Let us arrange our data points from least to greatest order.

0, 0, 2, 2, 2, 3, 4, 6, 8.

Let us find median of our data set. Since our data set has 9 data points, therefore, median of our given data set will be value of 5th term, that is 2.

Now let us find lower quartile, which is also known as the median of the data points to the left of median.

We have 4 data points to the left of our median, so our lower quartile will be average of 2nd and 3rd data point.

Q_1=\frac{0+2}{2}=\frac{2}{2}=1

Now let us find upper quartile of our given data set, which is the median of the data points to the right of median.

We have 4 data points to the right of the median, so our upper quartile will be the average of 7th and 8th data point.

Q_3=\frac{4+6}{2}=\frac{10}{2}=5

Since we know that interquartile range is the difference between upper and lower quartile.

IQR=Q_3-Q_1

IQR=5-1

IQR=4

Therefore, IQR of our given data set is 4.

8 0
4 years ago
Read 2 more answers
Use properties to find 4 times 23 times 25
erastova [34]
The answer to the problem is 2300
8 0
3 years ago
Read 2 more answers
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