I know solve 13but i want steps
2 answers:
From Pythagorean theorem in ADB triangle
AB^2+BD^2=AD^2
9^2+BD^2=15^2
BD=12
From Pythagorean theorem in BCD triangle
CD^2+BD^2=BC^2
BC^2=5^2+12^2
BC=13
Step-by-step explanation:
In triangle ABD,
ang.ABD=90°
AB=9 cm
AD=15 cm
Now,
Using Pythagoras theorem,
AD2=AB2+BD2(2=square)
or,152=92+BD2
or,225=81+BD2
or,225-81=BD2
or,144=BD2
or,BD=12 cm
Then,
In triangle CBD,
CD=5 cm
BD=12 cm
BC=?
Now,
Using Pythagoras theorem,
BC2=CD2+BD2
or,BC2=52+122
or,BC2=25+144
or,BC2=169
or,BC=13 cm
You might be interested in
C. p=75/r
......................
<span><span>ab:ac=3:5
bd:cd=7:2
if cd is 5 cm then cd=2:5 then ab=3:x
2:5=3:x
15=2x
x=15/2
x=7.5 cm</span><span>
Happy studying! ^_^</span></span>
Answer:
1) n= 20.5
2) t= -17/3
Step-by-step explanation:
1) -4n + 20 = -62
-4n = -82
n = 20.5
2) -3t = 17
t = -17/3
Y = k/x where k is the constant of variation
y = 3 , x = 1.2 gives
3 = k/1.2
therefore
k = 3*1.2 = 3.6
and the required equation is
y = 3.6 / x
There is no picture or anything but it’s ok .