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2 years ago

11

Someone help me . what’s the infinite solution or just what it says help please make sure right .

1 answer:

Gala2k [10]2 years ago

3 0

Answer:

yes it is right

Step-by-step explanation:

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Verify the identity. Show your work. 1 + sec^2xsin^2x = sec^2x

allsm [11]

$\bf \textit{Pythagorean Identities}
\\\\
1+tan^2(\theta)=sec^2(\theta)\\\\
-------------------------------\\\\
1+sec^2(x)sin^2(x)=sec^2(x)
\\\\\\
1+\cfrac{1}{cos^2(x)}\cdot sin^2(x)\implies 1+\cfrac{sin^2(x)}{cos^2(x)}\\\\\\ 1+tan^2(x)\implies sec^2(x)$

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3 years ago

You can set up a proportion:

nadya68 [22]

Answer:

15/30:2/30

15/30=2/30x

divide by 15/30

7.5 is x

Step-by-step explanation:

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2 years ago

Please help it’s matching and sentence length. I’m putting 20 points on this

Finger [1]

Answer:

What is the arc length and sector area for the following circle. Round your answer to 4 decimal places. *

Step-by-step explanation:

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2 years ago

Please any one help me

Ulleksa [173]

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

Since it's a Trapezoid with its non - parallel sides equal to one another,

$\qquad \sf \dashrightarrow \:\angle A + \angle P = 180$

[ By forming co - interior angle pair ]

$\qquad \sf \dashrightarrow \:\angle A +100 = 180$

$\qquad \sf \dashrightarrow \:\angle A = 180 - 100$

$\qquad \sf \dashrightarrow \:\angle A = 80$

Now, similarly,

$\qquad \sf \dashrightarrow \:\angle A + \angle R = 180$

$\qquad \sf \dashrightarrow \: \angle R + 80 = 180$

$\qquad \sf \dashrightarrow \: \angle R = 100$

Similarly,

$\qquad \sf \dashrightarrow \angle K + \angle R = 180$

$\qquad \sf \dashrightarrow \angle K + 100 = 180$

$\qquad \sf \dashrightarrow \angle K = 80$

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2 years ago

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Televisions are on sale for 85% of the original price of $499. How do I find out the sale price.

natulia [17]

To find your sale price you must:
$\frac{85}{100} \times 499 =$
just simply follow that operation and you're good to go

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3 years ago

Read 2 more answers